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hichkok12 [17]
3 years ago
15

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!! I CANNOT RETAKE THIS!!

Physics
1 answer:
Aneli [31]3 years ago
3 0

d^2=4^2+3^2\\\\d^2=16+9\\\\d^2=25\\\\d=5

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Henry was giving the school toy for his birthday he can use it to tell how fast someone is moving at the moment in time the toy
pochemuha

Answer:

The toy must calculate the person's speed/velocity

Explanation:

Since the school toy given to Henry can be used to tell how fast someone is moving, the toy must be able to calculate the person's speed/velocity using the <u>average distance</u> covered by the person divided by <u>time taken</u> to cover the distance; average distance ÷ time taken.

The toy must be able to determine the parameters (average distance and time taken) in order to be able to calculate the person's speed/velocity

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3 years ago
James took two pea plants, placing one in a dark closet and the other on a sunny window sill. Both are located in air-conditione
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The constant is the temperature of the air that the plants get.

The independent variable is the thing that YOU control.  That's the amount of sunlight each plant gets.

The <em>dependent variable</em> is anything that's caused by changes in the independent variable.  That's the growth of the plants.

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3 years ago
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How do the forces on a skydiver affect the velocity of the skydiver as they fall?<br><br><br> Hellp
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Explanation:

As a skydiver falls, he accelerates downwards, gaining speed with each second. The increase in speed is accompanied by an increase in air resistance. This force of air resistance counters the force of gravity.

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What are (a) the energy of a photon corresponding to wavelength 6.0 nm, (b) the kinetic energy of an electron with de Broglie wa
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Explanation:

Given that,

Wavelength = 6.0 nm

de Broglie wavelength = 6.0 nm

(a). We need to calculate the energy of photon

Using formula of energy

E = \dfrac{hc}{\lambda}

E=\dfrac{6.63\times10^{-34}\times3\times10^{8}}{6.0\times10^{-9}}

E=3.315\times10^{-17}\ J

(b).  We need to calculate the kinetic energy of an electron

Using formula of kinetic energy

\lambda=\dfrac{h}{\sqrt{2mE}}

E=\dfrac{h^2}{2m\lambda^2}

Put the value into the formula

E=\dfrac{(6.63\times10^{-34})^2}{2\times9.1\times10^{-31}\times(6.0\times10^{-9})^2}

E=6.709\times10^{-21}\ J

(c). We need to calculate the energy of photon

Using formula of energy

E = \dfrac{hc}{\lambda}

E=\dfrac{6.63\times10^{-34}\times3\times10^{8}}{6.0\times10^{-15}}

E=3.315\times10^{-11}\ J

(d). We need to calculate the kinetic energy of an electron

Using formula of kinetic energy

\lambda=\dfrac{h}{\sqrt{2mE}}

E=\dfrac{h^2}{2m\lambda^2}

Put the value into the formula

E=\dfrac{(6.63\times10^{-34})^2}{2\times9.1\times10^{-31}\times(6.0\times10^{-15})^2}

E=6.709\times10^{-9}\ J

Hence, This is the required solution.

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3 years ago
A coil of wire with 100. circular turns of radius 8.00 cm is in a uniform magnetic field along the axis of the coil. The resista
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