The energy required to raise the temperature of the air in a room by 5.0°C is 336 kJ
U =
m ΔT
U = Energy
= Specific heat
m = Mass
ΔT = Change in temperature
ρ = Density
V = Volume
ρ = 1000 g / m³ (Dry air )
= 1 J / g K
ΔT = 5 °C
V = 4 * 4 * 3
V = 48 m³
m = ρ V
m = 1000 * 48
m = 48000 g
U = 1 * 48000 * 7
U = 336000 J
U = 336 kJ
Therefore, the energy required to raise the temperature of the air in a room by 5.0°C is 336 kJ
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Answer and Explanation:
The estimation of the mass of the objects is as follows
Given that
The mass of an apple is about 100 g
Just like that, we do some estimation of different objects
A dime is around 1 g
A smartphone is about 100 g
An adult male is approx 100 kg
A college physics textbook is around 1 kg
A ripe banana is around 100 g
A small car is around 1,000 kg
Explanation:
It is given that,
Mass of the runner, m = 70 kg
Length of the tendon, l = 15 cm = 0.15 m
Area of cross section, 
Part A,
Let the runner's Achilles tendon stretch if the force on it is 8.0 times his weight, F = 8 mg
Young's modulus for tendon is, 
The formula of the Young modulus is given by :



Part B,
The fraction of the tendon's length does this correspond is given by :


Hence, this is the required solution.
(a) 
The relationship beween centripetal acceleration and angular speed is

where
is the angular speed
r is the radius of the circular path
Here we gave
is the centripetal acceleration
r = 5.15 m is the radius
Solving for
, we find:

(b) 21.3 m/s
The relationship between the linear speed and the angular speed is

where
v is the linear speed
is the angular speed
r is the radius of the circular path
In this problem we have

r = 5.15 m
Solving the equation for v, we find

Answer:
A. a rigorously tested explanation
Explanation:
- B. and D. are out - theories are not opinionated, they are factual
- C. is out - not all theories are mathematical
- A. is the best choice