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Neporo4naja [7]
3 years ago
12

A coil of wire with 100. circular turns of radius 8.00 cm is in a uniform magnetic field along the axis of the coil. The resista

nce is 40.0 O. At what rate, in teslas per second, must the magnetic field be changing to induce a current of 0.150 A in the coil?
1.59 T/s
2.98 T/s
6.00 T/s
9.38 T/s
Physics
1 answer:
andreyandreev [35.5K]3 years ago
6 0
I think Im gonna have to go with C 6.00 T/s but Im not sure
You might be interested in
Question 1 (1 point)
puteri [66]

Answer:

250 N

Explanation:

a =  \frac{vf - vi}{t}

Vf=final velocity

Vi =initial velocity

=70-20/2=25m/s^2

F=ma

=10kg * 25m/s^2

=250N

3 0
3 years ago
A student throws a water balloon vertically downward from the top of a building. The balloon leaves the thrower's hand with a sp
dusya [7]

from the question you can see that some detail is missing, using search engines i was able to get a similar question on "https://www.slader.com/discussion/question/a-student-throws-a-water-balloon-vertically-downward-from-the-top-of-a-building-the-balloon-leaves-t/"

here is the question : A student throws a water balloon vertically downward from the top of a building. The balloon leaves the thrower's hand with a speed of 60.0m/s. Air resistance may be ignored,so the water balloon is in free fall after it leaves the throwers hand. a) What is its speed after falling for 2.00s? b) How far does it fall in 2.00s? c) What is the magnitude of its velocity after falling 10.0m?

Answer:

(A) 26 m/s

(B) 32.4 m

(C) v = 15.4 m/s

Explanation:

initial speed (u) = 6.4 m/s

acceleration due to gravity (a) = 9.9 m/s^[2}

time (t) = 2 s

(A)   What is its speed after falling for 2.00s?

  from the equation of motion v = u + at we can get the speed

v = 6.4 + (9.8 x 2) = 26 m/s

(B) How far does it fall in 2.00s?

  from the equation of motion s=ut+0.5at^{2} we can get the distance covered

s = (6.4 x 2) + (0.5 x 9.8 x 2 x 2)

s = 12.8 + 19.6 = 32.4 m

c) What is the magnitude of its velocity after falling 10.0m?

from the equation of motion below we can get the velocity

v^{2} = u^{2} + 2as\\v^{2} = 6.4^{2} + (2x9.8x10)\\V^{2} = 236.96\\v = \sqrt{236.96}

v = 15.4 m/s

7 0
3 years ago
When an object moves in a circular path, it accelerates toward the center of the circle as a result of ______.
kolbaska11 [484]

Answer:

Centripetal acceleration

Explanation:

An object moving around a xirxular path maintains its route as a result of centripetal force. However, its acceleration is caused by centripetal acceleration. Despite centripetal acceleration not being among the choices, it is the right answer.

Centripetal acceleration helps an object that navigates around a circular path to accelerate while centripetal force enables the movement of an object around a circular path to move inwards. Momentum, given as one of the choices is product of mass and velocity while friction is the force opposing movement of an object around a surface.

3 0
3 years ago
A proton is located at <3 x 10^-10> m. What is r, the vector from the origin to the location of the proton
Eduardwww [97]

Complete Question

A proton is located at <3 x 10^{-10}, -5*10^{-10}  , -5*10^{-10}> m. What is r, the vector from the origin to the location of the proton

Answer:

The  vector position is   \=r=

Explanation:

From the question we are told that

  The  position of the proton is m

Generally the vector location of the proton is mathematically represented as

       \= r =

So substituting values

     \=r=

4 0
3 years ago
Why does data need to be reliable
Karolina [17]
So results can be shared and used by other scientists that want to use or replicate your experiment.
8 0
3 years ago
Read 2 more answers
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