∑F = ma
a = ∑F/m
a = 35 N / 5.4 kg
a = 6.5 m/s²
Answer:
The wavelength is ![\lambda_2 = 534 *10^{-9} \ m](https://tex.z-dn.net/?f=%5Clambda_2%20%3D%20%20534%20%2A10%5E%7B-9%7D%20%5C%20m)
Explanation:
From the question we are told that
The wavelength of the first light is ![\lambda _ 1 = 587 \ nm](https://tex.z-dn.net/?f=%5Clambda%20_%201%20%3D%20%20587%20%5C%20nm)
The order of the first light that is being considered is
The order of the second light that is being considered is
Generally the distance between the fringes for the first light is mathematically represented as
![y_1 = \frac{ m_1 * \lambda_1 * D}{d}](https://tex.z-dn.net/?f=y_1%20%3D%20%20%5Cfrac%7B%20m_1%20%20%2A%20%5Clambda_1%20%2A%20%20D%7D%7Bd%7D)
Here D is the distance from the screen
and d is the distance of separation of the slit.
For the second light the distance between the fringes is mathematically represented as
![y_2 = \frac{ m_2 * \lambda_2 * D}{d}](https://tex.z-dn.net/?f=y_2%20%3D%20%20%5Cfrac%7B%20m_2%20%20%2A%20%5Clambda_2%20%2A%20%20D%7D%7Bd%7D)
Now given that both of the light are passed through the same double slit
![\frac{y_1}{y_2} = \frac{\frac{m_1 * \lambda_1 * D}{d} }{\frac{m_2 * \lambda_2 * D}{d} } = 1](https://tex.z-dn.net/?f=%5Cfrac%7By_1%7D%7By_2%7D%20%20%3D%20%20%5Cfrac%7B%5Cfrac%7Bm_1%20%2A%20%20%5Clambda_1%20%2A%20D%7D%7Bd%7D%20%20%7D%7B%5Cfrac%7Bm_2%20%2A%20%20%5Clambda_2%20%2A%20D%7D%7Bd%7D%20%20%7D%20%3D%201)
=> ![\frac{ m_1 * \lambda _1 }{ m_2 * \lambda_2} = 1](https://tex.z-dn.net/?f=%5Cfrac%7B%20m_1%20%2A%20%20%5Clambda%20_1%20%20%7D%7B%20m_2%20%20%2A%20%20%5Clambda_2%7D%20%3D%20%201)
=> ![\lambda_2 = \frac{m_1 * \lambda_1}{m_2}](https://tex.z-dn.net/?f=%5Clambda_2%20%3D%20%20%5Cfrac%7Bm_1%20%2A%20%20%5Clambda_1%7D%7Bm_2%7D)
=> ![\lambda_2 = \frac{10 * 587 *10^{-9}}{11}](https://tex.z-dn.net/?f=%5Clambda_2%20%3D%20%20%5Cfrac%7B10%20%20%2A%20%20%20587%20%2A10%5E%7B-9%7D%7D%7B11%7D)
=> ![\lambda_2 = 534 *10^{-9} \ m](https://tex.z-dn.net/?f=%5Clambda_2%20%3D%20%20534%20%2A10%5E%7B-9%7D%20%5C%20m)
Answer:
the sun's heat affects humidity of how warm the air feels to us.
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It’s D. An enlargement (hope this helps!)
Answer:
The charge on the third object is − 21.7nC
Explanation:
From Gauss's Law
Φ = Q/ε₀
where;
Φ is the total electric flux through the shell = − 533 N⋅m²/C
Q is the total charge Q in the shell = ?
ε₀ is the permittivity of free space = 8.85 x 10⁻¹²
From this equation; Φ = Q/ε₀
Q = Φ * ε₀ = − 533 * 8.85 x 10⁻¹²
Q = −4.7 X 10⁻⁹ C = -4.7nC
Q = q₁ + q₂ + q₃
− 4.7nC = − 14.0 nC + 31.0 nC + q₃
− 4.7nC − 17nC = q₃
− 21.7nC = q₃
Therefore, the charge on the third object is − 21.7nC