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kenny6666 [7]
3 years ago
7

The chief by 3 3/4 kg of Apple's 7 1/4 kilograms of peers and 10 1/8 kilograms with orange about how many kilograms of fruit did

the chief by all together
Physics
2 answers:
WARRIOR [948]3 years ago
7 0
SOLUTION:

Total amount of fruit = Total amount of apples + Total amount of pears + Total amount of oranges

Total amount of fruit = 15 / 4 + 29 / 4 + 81 / 8

Total amount of fruit = 30 / 8 + 58 / 8 + 81 / 8

Total amount of fruit = 169 / 8

Total amount of fruit = 21.125 kg

ANSWER:

Therefore, the chief bought 21.125 kg of fruit all together.

Please mark as brainliest if you found this helpful! :)
Thank you <3
anastassius [24]3 years ago
3 0

(3 3/4) + (7 1/4) + (10 1/8)

Change the mixed numbers to fractions:

(15/4) + (29/4) + (81/8)

Write all of the fractions with a common denominator (8):

(30/8) + (58/8) + (81/8)

Add the fractions:

(30 + 58 + 81) / 8  =  169/8

Change the sum back to a mixed number:

169/8 = <em>21 and 1/8 kg.</em>

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A quarter is flipped from a height of 1.45 m above the ground. How much time will it take to reach the ground if the person flip
Artemon [7]

It will take the quarter 0.151 seconds to reach the ground.

<u>Given the following data:</u>

  • Height = 1.45 meters
  • Initial velocity = 10.32 m/s

We know that acceleration due to gravity (a) for an object is equal to 9.8 meter per seconds square.

To find how much time it will take the quarter to reach the ground, we  would use the second equation of motion.

Mathematically, the second equation of motion is given by the formula;

S = ut + \frac{1}{2} at^2

Where:

  • S is the height or distance covered.
  • u is the initial velocity.
  • a is the acceleration.
  • t is the time measured in seconds.

Substituting the values into the formula, we have;

1.45 = 10.32(t) + \frac{1}{2} (9.8)t^2\\\\1.45 = 10.32t + 4.9t^2\\\\4.9t^2 + 10.32t - 1.45 = 0

The standard form of a quadratic equation is:

ax^2 + bx + c = 0

a = 4.9, b = 10.32 and c = 1.45

We would solve the above quadratic equation by using the quadratic equation formula;

x = \frac{-b\; \pm \;\sqrt{b^2 - 4ac}}{2a}

Substituting the values, we have;

t = \frac{-10.32\; \pm \;\sqrt{10.32^2\; - \;4(4.9)(1.45)}}{2(4.9)}\\\\t = \frac{-10.32\; \pm \;\sqrt{106.5024\; - \;28.42}}{9.8}\\\\t = \frac{-10.32\; \pm \;\sqrt{78.0824}}{9.8}\\\\t = \frac{-10.32\; \pm \;8.84}{9.8}\\\\t = \frac{-10.32\; + \;8.84}{9.8}\\\\t = \frac{1.48}{9.8}

<em>Time, t = 0.151 seconds.</em>

Therefore, it will take the quarter 0.151 seconds to reach the ground.

Read more: brainly.com/question/8898885

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2 years ago
Should the hypothesis always be correct for a conclusion
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A simple pendulum 2 m long swings through a maximum angle of 30 ? with the vertical.
Alexus [3.1K]
The complete question was calculate the period T assuming the smallest amplitude.
Using the equation;
T = 2 π√(L/g)
Where T is the period in seconds, L is the length of the rod or wire in meters and g is the acceleration due to gravity. 
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A kangaroo jumps straight up to a vertical height of 1.66 m. How long was it in the air before returning to Earth? Express your
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Answer:

The kangaroo was 1.164s in the air before returning to Earth

Explanation:

For this we are going to use the equation of distance for an uniformly accelerated movement, that is:

x = x_{0} + V_{0}t + \frac{1}{2}at^2

Where:

x = Final distance

xo = Initial point

Vo = Initial velocity

a = Acceleration

t = time

We have the following values:

x = 1.66m      

xo = 0m (the kangaroo starts from the floor)

Vo = 0 m/s (each jump starts from the floor and from a resting position)

a = 9.8 m/s^2 (the acceleration is the one generated by the gravity of earth)

t =This is just the time it takes to the kangaoo reach the 1.66m, we don't know the value.

Now replace the values in the equation

x = x_{0} + V_{0}t + \frac{1}{2}at^2

1.66 = 0 + 0t + \frac{1}{2}9.8t^2

1.66 = 4.9t^2

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It takes to the kangaroo 0.582s to go up and the same time to go down then the total time it is in the air before returning to earth is

t = 0.582s + 0.582s

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