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kenny6666 [7]
3 years ago
7

The chief by 3 3/4 kg of Apple's 7 1/4 kilograms of peers and 10 1/8 kilograms with orange about how many kilograms of fruit did

the chief by all together
Physics
2 answers:
WARRIOR [948]3 years ago
7 0
SOLUTION:

Total amount of fruit = Total amount of apples + Total amount of pears + Total amount of oranges

Total amount of fruit = 15 / 4 + 29 / 4 + 81 / 8

Total amount of fruit = 30 / 8 + 58 / 8 + 81 / 8

Total amount of fruit = 169 / 8

Total amount of fruit = 21.125 kg

ANSWER:

Therefore, the chief bought 21.125 kg of fruit all together.

Please mark as brainliest if you found this helpful! :)
Thank you <3
anastassius [24]3 years ago
3 0

(3 3/4) + (7 1/4) + (10 1/8)

Change the mixed numbers to fractions:

(15/4) + (29/4) + (81/8)

Write all of the fractions with a common denominator (8):

(30/8) + (58/8) + (81/8)

Add the fractions:

(30 + 58 + 81) / 8  =  169/8

Change the sum back to a mixed number:

169/8 = <em>21 and 1/8 kg.</em>

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3 years ago
An object at rest on a flat, horizontal surface explodes into two fragments, one seven times as massive as the other. The heavie
Veronika [31]

Answer:

Explanation:

Given that,

One fragment is 7 times heavier than the other

Let one fragment mass be M

Let this has a velocity v

And the other 7M

And this a velocity V

Initially the fragment is at rest u = 0

Applying conservation of momentum

Momentum is given as p=mv

Initial momentum = final momentum

Po = Pf

(M+7M) × 0 = 7M •V − Mv

0 = 7M•V - Mv

Divide both sides by M

0 = 7V -v

v = 7V

Since friction decelerates the masses to zero speed, we can calculate the NET work on the individual blocks and relate this quantity to the change in kinetic energy of each block

The workdone by the 7M mass is

Distance moved by 7M mass is 6.8m, Then, d =6.8m

W = fr × d

Where fr = µkN

When N=W =mg, where m=7M

N= 7Mg

fr = −µk × 7mg

Then, W(7m) = −7µk•Mg×d

W(7m) = −7µk•Mg×6.8

W(7m) = −47.6 µk•Mg

Then, same procedure,

Let distance move by the small mass be m

Work done by M mass

W(m) = −µk•Mg×d'

Since it is a wordone by friction, that is why we have a negative sign.

Using conservation of energy

Work done by 7M mass is equal to work done by M mass

W(7m) = W(m)

−47.6 µk•Mg = −µk•Mg×d

Then, M, g and µk cancels out

We are left with

-46.7 = -d

Then, d = 46.7m

7 0
3 years ago
Read 2 more answers
Using a 683 nm wavelength laser, you form the diffraction pattern of a 1.1 mm wide slit on a screen. You measure on the screen t
n200080 [17]

Answer:

10.2 m

Explanation:

The position of the dark fringes (destructive interference) formed on a distant screen in the interference pattern produced by diffraction from a single slit are given by the formula:

y=\frac{\lambda (m+\frac{1}{2})D}{d}

where

y is the position of the m-th minimum

m is the order of the minimum

D is the distance of the screen from the slit

d is the width of the slit

\lambda is the wavelength of the light used

In this problem we have:

\lambda=683 nm = 683\cdot 10^{-9} m is the wavelength of the light

d=1.1 mm = 0.0011 m is the width of the slit

m = 13 is the order of the minimum

y=8.57 cm = 0.0857 m is the distance of the 13th dark fringe from the central maximum

Solving for D, we find the distance of the screen from the slit:

D=\frac{yd}{\lambda(m+\frac{1}{2})}=\frac{(0.0857)(0.0011)}{(683\cdot 10^{-9})(13+\frac{1}{2})}=10.2 m

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