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Reika [66]
3 years ago
14

Find the equation (in terms of x) of the line through the points ( − 1 , − 1 ) and( 4 , − 4 )

Mathematics
1 answer:
mrs_skeptik [129]3 years ago
7 0

Answer:

y = -\frac{3}{5}x -\frac{8}{5}

Step-by-step explanation:

Given

(x_1,y_1) = (-1,-1)

(x_2,y_2) = (4,-4)

Required

Determine the line equation

First, calculate the slope (m)

m = \frac{y_2 - y_1}{x_2 - x_1}

m = \frac{-4 - (-1)}{4 - (-1)}

m = \frac{-4 +1}{4 +1}

m = \frac{-3}{5}

m = -\frac{3}{5}

The equation is then calculated using:

y - y_1 = m(x - x_1)

This gives:

y - (-1) = -\frac{3}{5}(x - (-1))

y + 1 = -\frac{3}{5}(x +1))

Open bracket

y + 1 = -\frac{3}{5}x -\frac{3}{5}

Make y the subject

y = -\frac{3}{5}x -\frac{3}{5}-1

y = -\frac{3}{5}x +\frac{-3-5}{5}

y = -\frac{3}{5}x +\frac{-8}{5}

y = -\frac{3}{5}x -\frac{8}{5}

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Nata [24]
How much part can sally paint in an hour ?
a ÷ 7 = a/7

And what about Steve ?
a ÷ 9 = a/9

Where, a is the total area of the room.

So, let the time taken by both of them to paint the room together be 't'

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t(a/7 + a/9) = a
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6 0
3 years ago
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Felicia wants to build a kite with the shape shown. If AC is 60 cm, how many centimeters are in the length of BD?
Kay [80]

Answer:

Step-by-step explanation:

By applying tangent rule in the given right triangle AOB,

tan(30°) = \frac{\text{Opposite side}}{\text{Adjacent side}}

\frac{1}{\sqrt{3}}=\frac{BO}{OA}

OA=BO(\sqrt{3})

By applying tangent rule in the given right triangle BOC,

tan(60°) = \frac{OC}{BO}

OC = BO(√3)

OA + OC = AC

BO(\sqrt{3})+BO(\sqrt{3}) =60

2√3(BO) = 60

BO = 10√3

OC = BO(√3)

OC = (10√3)(√3)

OC = 30

By applying tangent rule in right triangle DOC,

tan(60°) = \frac{OD}{OC}

OD = OC(√3)

OD = 30√3

Since, BD = BO + OD

BD = 10√3 + 30√3

BD = 40√3

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6 0
2 years ago
How many different twotwo​-letter passwords can be formed from the letters
Anna [14]

Answer:

70

Step-by-step explanation:

GIVEN: two two​-letter passwords can be formed from the letters  A, B, C, D, E, F, G and H.

TO FIND: How many different two two​-letter passwords can be formed if no repetition of letters is​ allowed.

SOLUTION:

Total number of different letters =8

for two two​-letter passwords 4 different are required.

Number of ways of selecting 4 different letters from 8 letters=^8C_4

                                                                                                   =\frac{8!}{4!4!}

                                                                                                  =70

Hence there are 70 different two-letter passwords can be formed using 8 letters.

5 0
3 years ago
The art teacher has 48 boxes of crayons.
xz_007 [3.2K]

Answer:

3072 Crayons

Step-by-step explanation:

Crayons = C

48C * 64C = 3072C

3072C = 3072 Crayons

8 0
3 years ago
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