1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
dangina [55]
3 years ago
12

Evaluate. 102+6⋅7+8 70142150190

Mathematics
2 answers:
Aloiza [94]3 years ago
6 0
Hi.

102+6(7)+8  (your equation)
102+ 42+ 8  (since the order is PEMDAS, multiplication has to go first. 6x7=42
144 + 8        (since you go left to right, 102 +42 has to be 1st. Answer= 144)
152              (now the only thing left is 144 + 8, so do that. Answer= 152.)

Since that's the last step, 152 will be your answer. 

Hoped I helped and if you need anymore you could always ask me~ 

-Dawn

Alinara [238K]3 years ago
3 0

Answer:

<u>150</u>

Step-by-step explanation:

The 102 was supposed to be 10². I know this because it was on my test. (I'm in 6th grade, I made this acc for my bro tho. I'm ahead of my class TWT)

Step-by-step solving:

10² + 6 • 7 + 8

100 + 6 • 7 + 8

100 + 42 +8

142 + 8

<em>150</em>

<em />

<em>(Bolded is the part of the expression being solved)</em>

You might be interested in
1. Simplify the expression. Assume that
ololo11 [35]

Answer:

b. 6|x|

Step-by-step explanation:

√(36x²) = √36√(x²)= 6|x|

Because √ from the number can be only positive.

5 0
3 years ago
PLEASE HELPPPPPPPPPPPPPP THANK YOUUH
almond37 [142]
For A B and C, you just plug in the given number

A
2(15) + 5 = 35
B
4(20) + 2 = 82
C
6(10) + 5 = 65
And for D, you set the equation to 26 and solve for n
3x + 5 = 26 \\ 3x = 21 \\ x = 7
I had to use x instead of n, but for D n=7. :)

8 0
3 years ago
The graph below represents the solution set of which inequality?
natulia [17]

Answer:

option: B (x^2+2x-8) is correct.

Step-by-step explanation:

We are given the solution set as seen from the graph as:

(-4,2)

1)

On solving the first inequality we have:

x^2-2x-8

On using the method of splitting the middle term we have:

x^2-4x+2x-8

⇒  x(x-4)+2(x-4)=0

⇒ (x+2)(x-4)

And we know that the product of two quantities are negative if either one of them is negative so we have two cases:

case 1:

x+2>0 and x-4

i.e. x>-2 and x<4

so we have the region as:

(-2,4)

Case 2:

x+2 and x-4>0

i.e. x<-2 and x>4

Hence, we did not get a common region.

Hence from both the cases we did not get the required region.

Hence, option 1 is incorrect.

2)

We are given the second inequality as:

x^2+2x-8

On using the method of splitting the middle term we have:

x^2+4x-2x-8

⇒ x(x+4)-2(x+4)

⇒ (x-2)(x+4)

And we know that the product of two quantities are negative if either one of them is negative so we have two cases:

case 1:

x-2>0 and x+4

i.e. x>2 and x<-4

Hence, we do not get a common region.

Case 2:

x-2 and x+4>0

i.e. x<2 and x>-4

Hence the common region is (-4,2) which is same as the given option.

Hence, option B is correct.

3)

x^2-2x-8>0

On using the method of splitting the middle term we have:

x^2-4x+2x-8>0

⇒ x(x-4)+2(x-4)>0

⇒ (x-4)(x+2)>0

And we know that the product of two quantities are positive if either both of them are negative or both of them are positive so we have two cases:

Case 1:

x+2>0 and x-4>0

i.e. x>-2 and x>4

Hence, the common region is (4,∞)

Case 2:

x+2 and x-4

i.e. x<-2 and x<4

Hence, the common region is: (-∞,-2)

Hence, from both the cases we did not get the desired answer.

Hence, option C is incorrect.

4)

x^2+2x-8>0

On using the method of splitting the middle term we have:

x^2+4x-2x-8>0

⇒ x(x+4)-2(x+4)>0

⇒ (x-2)(X+4)>0

And we know that the product of two quantities are positive if either both of them are negative or both of them are positive so we have two cases:

Case 1:

x-2 and x+4

i.e. x<2 and x<-4

Hence, the common region is: (-∞,-4)

Case 2:

x-2>0 and x+4>0

i.e. x>2 and x>-4.

Hence, the common region is: (2,∞)

Hence from both the case we do not have the desired region.

Hence, option D is incorrect.




5 0
3 years ago
RSM wants to send four of its 18 Math Challenge teachers to a conference. How many combinations of four teachers include exactly
tatiyna

Answer:

1120 combinations of four teachers include exactly one of either Mrs. Vera or Mr. Jan.

Step-by-step explanation:

The order in which the teachers are chosen is not important, which means that the combinations formula is used to solve this question.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

In this question:

1 from a set of 2(Either Mrs. Vera or Mr. Jan).

3 from a set of 18 - 2 = 16. So

C_{2,1}C_{16,3} = \frac{2!}{1!1!} \times \frac{16!}{3!13!} = 1120

1120 combinations of four teachers include exactly one of either Mrs. Vera or Mr. Jan.

4 0
3 years ago
Is it
Hatshy [7]

Answer:

B. 90 degrees counterclockwise

Step-by-step explanation:

7 0
2 years ago
Other questions:
  • Solve2x^2 + 3x = 5 by factoring
    12·2 answers
  • Lila drives 129 kilometers round trip to work. how many kilometers does she drive in 31 days
    14·2 answers
  • Please help urgent!!
    11·1 answer
  • Mia and Elizabeth share a reward of $140 in a ratio of 2:5. what fraction of the total reward does mia have?
    8·1 answer
  • A day at Camp there were 56 girls and 42 boys the campers need to be split into equal groups each has either all girls are all b
    12·1 answer
  • James answered 84% of the test questions correctly. He answered 21 questions correctly. How many questions were on the test?
    8·1 answer
  • What are the coordinates of the x-intercepts of the graph of y = 2x2 + 6x – 20? A) (–5, 0) , (2, 0) . B) (5, 0) , (–2, 0) . C) (
    13·1 answer
  • Which equation has the same solution as x^2+8x-33 =0 ?
    12·1 answer
  • Which number line represents the solution set for the inequality-1/2x&gt;_4
    9·1 answer
  • Please help me solve this, thank you.
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!