1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
jek_recluse [69]
3 years ago
8

An electronics company wants to compare the quality of their cell phones to the cell phones from three of their competitors. The

y sample 10 phones from each of the four companies and count the number of defects for each phone. If ANOVA was used to compare the average number of defects, then the treatments would be defined as: ______.
Mathematics
1 answer:
Arlecino [84]3 years ago
4 0

Answer:

The treatment should be stated by the four companies,since it more interested in the quality among each of the companies to be compared.

Step-by-step explanation:

You might be interested in
The gas law for an ideal gas at absolute temperature T (in kelvins), pressure P (in atmospheres), and volume V (in liters) is PV
JulijaS [17]

Answer:

\frac{dT}{dt}=3.78^{\circ}K/min

Step-by-step explanation:

We have to calculate the time derivative of T=PV/nR with P and V variable and n and R constants. This is:

\frac{dT}{dt} =\frac{d\frac{PV}{nR}}{dt}=\frac{1}{nR}\frac{d(PV)}{dt}

What we have to do is the derivative of a product:

\frac{d(PV)}{dt}=P\frac{dV}{dt}+V\frac{dP}{dt}

Substituting, we have:

\frac{dT}{dt} =\frac{P\frac{dV}{dt}+V\frac{dP}{dt}}{nR}

where all these values are given since the time derivatives of P and V are their variation rate, using minutes.

We then substitute everything, noticing that already everything is in the same system of units so they cancel out:

\frac{dT}{dt}=\frac{P\frac{dV}{dt}+V\frac{dP}{dt}}{nR}=\frac{(8atm)(0.16L/min)+(13L)(0.14atm/min)}{(10mol)(0.0821Latm/mol^{\circ}K)}

And then just calculate:

\frac{dT}{dt}=3.78^{\circ}K/min

6 0
3 years ago
Prove that 4x-1 =11,in which the value of x=3​
SOVA2 [1]

Answer:

3

Step-by-step explanation:

substitute where x=3 into the equation

so 4*3-1=11

8 0
3 years ago
Read 2 more answers
56 out of 154 in simplest form of a fraction
marissa [1.9K]
We start with 56/154.  Dividing each number by two, we have:

28/77

Dividing each number by seven, we have:

4/11

As the greatest common factor of 4 and 11 is 1, this fraction is in simplest form.  Thus, 56/154 is equal to 4/11.
4 0
3 years ago
Read 2 more answers
Covert 110% to a decimal
omeli [17]
That would be 1.1 in decimals.
5 0
3 years ago
The Fish and Game Department stocked a lake with fish in the following proportions: 30% catfish, 15% bass, 40% bluegill, and 15%
vagabundo [1.1K]

Answer:

1) \chi^2 =\frac{(112-150)^2}{150}+\frac{(95-75)^2}{75}+\frac{(210-200)^2}{200}+\frac{(83-75)^2}{75}=16.313

2) p_v =P(\chi^2_{3}>16.313)=0.000978

And we got the same decision reject the null hypothesis at 5% of significance.

Step-by-step explanation:

Previous concepts

The Chi-Square test of independence is used "to determine if there is a significant relationship between two nominal (categorical) variables". And is defined with the following statistic:

\chi^2 =\sum_{i=1}^n \frac{(O-E)^2}{E}

Where O rpresent the observed values and E the expected values.  

State the null and alternative hypothesis

Null hypothesis: The distribution  is 30% catfish, 15% bass, 40% bluegill, and 15% pike

Alternative hypothesis: The distribution  is NOT 30% catfish, 15% bass, 40% bluegill, and 15% pike

The observed values are given by the table given:

Catfish =112, BAss = 95, Bluegill=210, Pike=83

Calculate the expected values

In order to calculate the expected values we can use the following formula for each cell of the table

E = \% Grand total

E_{Catfish}=500*0.3=150

E_{Bass}=500*0.15=75

E_{Bluegill}=500*0.4=200

E_{Pike}=500*0.15=75

Part 1: Calculate the statistic

\chi^2 =\frac{(112-150)^2}{150}+\frac{(95-75)^2}{75}+\frac{(210-200)^2}{200}+\frac{(83-75)^2}{75}=16.313

\chi^2 =16.313

Calculate the critical value

First we need to calculate the degrees of freedom given by:

df= (categories-1)=(4-1)= 3

Since the confidence provided is 95% the significance would be \alpha=1-0.95=0.05 and we can find the critical value with the following excel code: "=CHISQ.INV(0.95,3)", and our critical value would be \chi^2_{crit}=7.815

We can calculate also the p value:

p_v =P(\chi^2_{3}>16.313)=0.000978

And we got the same decision reject the null hypothesis at 5% of significance.

5 0
3 years ago
Other questions:
  • if you had a block of each type of wood with the same dimensions,how would their weights compare?explain?
    8·2 answers
  • Please someone help. I am in need of a response...
    8·1 answer
  • Divide 254 by 11.8. round your answer to the nearest hundredth.
    11·2 answers
  • 420÷14 show picture please
    14·2 answers
  • i need help quick!! this is unit 1:geometry basics. homework 5: angle relationships if anyone know tell me
    6·2 answers
  • Please help with the two questions above! I will give brainliest to the correct answers. Thanks!
    10·1 answer
  • Find the gradient of the line segement between the points (0,-6) and (2,-16)
    9·1 answer
  • Help, I don’t understand this DeltaMath question
    15·1 answer
  • seven times a number is twelve more than three times the number. write an equation, this is urgent! pls hurry up!
    5·2 answers
  • PLS HELP ASAP THANKS ILL GIVE BRAINLKEST PLS THANKS PLS ASAP PLS PLS HELP ASAP THANKS
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!