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3 years ago

Help with this last question please

Mathematics

1 answer:

Wewaii [24]3 years ago

8 0

Fourth one is the right one

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Given f(x)=1/4(5-x)2 what is the value of f(11)

iren [92.7K]

Answer:

f(x)=1/4(5-x)²

Step-by-step explanation:

f(11)=1/4(5-11)²

1/4(-6)²

1/4(36)

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2 years ago

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Natalie walk 3/5 mile and a 1/2 hour . how fast did she walk in in miles per hour?

Talja [164]

She walks 6/5 of a mile in 1 hour

So, she walks 1.2 miles per hour

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3 years ago

What is 0.216 (26 recurring) as a fraction?

ankoles [38]

216/1000

Simplify it by 2

Give me a thanks if it helps!!!

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3 years ago

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Simplify. If d = –3, evaluate –d. –3 1 0 3

AnnZ [28]

-d would equal 3. just flip its around right?

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3 years ago

The total monthly profit for a firm is P(x)=6400x−18x^2− (1/3)x^3−40000 dollars, where x is the number of units sold. A maximum

wlad13 [49]

Answer:

Maximum profits are earned when x = 64 that is when 64 units are sold.

Maximum Profit = P(64) = 2,08,490.666667$

Step-by-step explanation:

We are given the following information: $P(x) = 6400x - 18x^2 - \frac{x^3}{3} - 40000$ , where P(x) is the profit function.

We will use double derivative test to find maximum profit.

Differentiating P(x) with respect to x and equating to zero, we get,

$\displaystyle\frac{d(P(x))}{dx} = 6400 - 36x - x^2$

Equating it to zero we get,

$x^2 + 36x - 6400 = 0$

We use the quadratic formula to find the values of x:

$x = \displaystyle\frac{-b \pm \sqrt{b^2 - 4ac} }{2a}$ , where a, b and c are coefficients of $x^2, x^1 , x^0$ respectively.

Putting these value we get x = -100, 64

Now, again differentiating

$\displaystyle\frac{d^2(P(x))}{dx^2} = -36 - 2x$

At x = 64, $\displaystyle\frac{d^2(P(x))}{dx^2} < 0$

Hence, maxima occurs at x = 64.

Therefore, maximum profits are earned when x = 64 that is when 64 units are sold.

Maximum Profit = P(64) = 2,08,490.666667$

6 0

3 years ago