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Nonamiya [84]
3 years ago
8

Help with this last question please

Mathematics
1 answer:
Wewaii [24]3 years ago
8 0
Fourth one is the right one
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3c+2d=-24 and 2c+5d= -38
Assoli18 [71]

Answer:

c=-4, d=-6

Step-by-step explanation:

3 0
2 years ago
How are average I.Q.s related to normal distributions?
Flauer [41]

In USA the average I.Q. is 98 while the top one average I.Q. country is Hong Kong.

But the I.Q. distribution is given by a polinomial graph, few people with extremely low I.Q. 40~70, a lot between 70~100, some between 100~120, few between 120~140 and extremely low 140+

8 0
2 years ago
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It looks easy i just dont know how to do it can someone help me out
Arada [10]

Answer:

16

Step-by-step explanation:

16+4x = 10 +14

-16             -16

4x = 8

/4      /4

x=2

8x=8(2)

=16

3 0
2 years ago
Monica asked her friends to buy a charity raffle ticket for $3. All but 4 of her friends bought a ticket, and she raised $18. Ho
Dafna11 [192]

Answer:

She asked 10 friends to buy tickets.

Step-by-step explanation:

If each ticket sells for 3 dollars, you can get the amount of people that bought the tickets by taking the amount earned divided by the price of the ticket.

$18 / $3 = 6

If 6 friends bought tickets and 4 friends did not, add the two together and you will get how much people Monica asked.

6 + 4 = 10

She asked 10 friends to buy tickets.

5 0
3 years ago
Read 2 more answers
Which polynomial function has a leading coefficient of 1 and roots (7 i) and (5 – i) with multiplicity 1? f(x) = (x 7)(x – i)(x
Nuetrik [128]

It looks like you might have intended to say the roots are 7 + i and 5 - i, judging by the extra space between 7 and i.

The simplest polynomial with these characteristics would be

f(x) = (x - (7 + i)) (x - (5 - i))

but seeing as each of the options appears to be a quartic polynomial, I suspect f(x) is also supposed to have only real coefficients. In that case, we need to pair up any complex root with its conjugate to "complete" f(x). We end up with

f(x) = (x - (7 + i)) (x - (7 - i)) (x - (5 - i)) (x - (5 + i))

which appears to most closely resemble the third option. Upon expanding, we see f(x) does indeed have real coefficients:

f(x) = (x^2 - (7^2 - i^2)) (x^2 - (5^2 - i^2)) = (x^2 - 8) (x^2 - 6) = x^4 - 14x^2 + 48

5 0
2 years ago
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