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Lostsunrise [7]
4 years ago
11

What is the mode of the data? 4,3,2,1,0,2,3,1,4,3

Mathematics
1 answer:
AURORKA [14]4 years ago
8 0

Answer: 3

Step-by-step explanation:

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Need help with this question too, just took a guess, but cannot explain or not sure if it's correct, please see pic for math pro
Oksi-84 [34.3K]

Answer:

0 ≤ x ≤ 70

Step-by-step explanation:

The range is defined by all values in the y-axe that are represented in the graph. In this case, we see the graph goes from 0 to 70, that will be the range.

PD. The representation is a non function.

5 0
3 years ago
I need help with #9 please
zepelin [54]
The median would decrease because the temperature given is lower than the median
5 0
3 years ago
Suppose that f: R --> R is a continuous function such that f(x +y) = f(x)+ f(y) for all x, yER Prove that there exists KeR su
Pachacha [2.7K]
<h2>Answer with explanation:</h2>

It is given that:

f: R → R is a continuous function such that:

f(x+y)=f(x)+f(y)------(1)  ∀  x,y ∈ R

Now, let us assume f(1)=k

Also,

  • f(0)=0

(  Since,

f(0)=f(0+0)

i.e.

f(0)=f(0)+f(0)

By using property (1)

Also,

f(0)=2f(0)

i.e.

2f(0)-f(0)=0

i.e.

f(0)=0  )

Also,

  • f(2)=f(1+1)

i.e.

f(2)=f(1)+f(1)         ( By using property (1) )

i.e.

f(2)=2f(1)

i.e.

f(2)=2k

  • Similarly for any m ∈ N

f(m)=f(1+1+1+...+1)

i.e.

f(m)=f(1)+f(1)+f(1)+.......+f(1) (m times)

i.e.

f(m)=mf(1)

i.e.

f(m)=mk

Now,

f(1)=f(\dfrac{1}{n}+\dfrac{1}{n}+.......+\dfrac{1}{n})=f(\dfrac{1}{n})+f(\dfrac{1}{n})+....+f(\dfrac{1}{n})\\\\\\i.e.\\\\\\f(\dfrac{1}{n}+\dfrac{1}{n}+.......+\dfrac{1}{n})=nf(\dfrac{1}{n})=f(1)=k\\\\\\i.e.\\\\\\f(\dfrac{1}{n})=k\cdot \dfrac{1}{n}

Also,

  • when x∈ Q

i.e.  x=\dfrac{p}{q}

Then,

f(\dfrac{p}{q})=f(\dfrac{1}{q})+f(\dfrac{1}{q})+.....+f(\dfrac{1}{q})=pf(\dfrac{1}{q})\\\\i.e.\\\\f(\dfrac{p}{q})=p\dfrac{k}{q}\\\\i.e.\\\\f(\dfrac{p}{q})=k\dfrac{p}{q}\\\\i.e.\\\\f(x)=kx\ for\ all\ x\ belongs\ to\ Q

(

Now, as we know that:

Q is dense in R.

so Э x∈ Q' such that Э a seq belonging to Q such that:

\to x )

Now, we know that: Q'=R

This means that:

Э α ∈ R

such that Э sequence a_n such that:

a_n\ belongs\ to\ Q

and

a_n\to \alpha

f(a_n)=ka_n

( since a_n belongs to Q )

Let f is continuous at x=α

This means that:

f(a_n)\to f(\alpha)\\\\i.e.\\\\k\cdot a_n\to f(\alpha)\\\\Also\\\\k\cdot a_n\to k\alpha

This means that:

f(\alpha)=k\alpha

                       This means that:

                    f(x)=kx for every x∈ R

4 0
3 years ago
If (5-3i)(x+iy)/(4-5i) = (2+i)^2-(3-4i)^2, then x=___ and y=____
Leona [35]
This looks complicated

lets simplify both sides

By multiplying top and bottom by the conjugate:-

left side  =  (5-3i)(x + iy) (4+5i)          (5-3i)(x + iy) (4+5i) 
                  ------------------------   =      ------------------------
                        (4-5i)(4+5i)                           41

right side =  (2 + i + 3-4)(2+i - 3 + 4i)    (by  Difference of 2 squares)

               =  5-3i)(-1 + 4i)

so as left side = right side

(5-3i)(x+yi)(4+5i)   = 41 (5-3i)(-1+5i)

5-3i is common so:-

(x + iy)(4+5i) = 41(-1+5i)

4x +5xi + 4yi - 5y = -41 + 205i

4x - 5y + (5x + 4y)i = -41 + 205i

EQuating coefficients we are left with the system of equations

4x -  5y = -41
5x + 4y  = 205

solving this gives x = 21 and y = 25


8 0
3 years ago
V(x)=-x^2+14x-57 I need help
eimsori [14]
Ohhhh my use photo math that stuff works 
6 0
4 years ago
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