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mihalych1998 [28]
3 years ago
10

What is the sum of -1/2 and 8/6 please help

Mathematics
1 answer:
SCORPION-xisa [38]3 years ago
4 0
Answer is C or 5/6
Explanation: use calculator
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How would you do this problem?
sweet [91]
F(x)=-5t^2+20t+60
Divide everything by -5
f(x)=t^2-4t-12
(t-6)(t+2)
Set it up to zero
t-6=0. t+2=0
t=6. t=-2
Since you can’t have negative seconds, the answer is 6 seconds
3 0
3 years ago
Read 2 more answers
When the author visited Dublin, Ireland (home of Guinness Brewery employee William Gosset, who first developed the t distributio
disa [49]

Answer:

The  Decision Rule

Fail to reject the null hypothesis

The conclusion

 There is no sufficient evidence to support the claim that the mean age of the cars is greater than that of taxi

Step-by-step explanation:

From the question we are told that

   The data is  

      Car Ages 4 0 8 11 14 3 4 4 3 5 8 3 3 7 4 6 6 1 8 2 15 11 4 1 6 1 8

     Taxi Ages 8 8 0 3 8 4 3 3 6 11 7 7 6 9 5 10 8 4 3 4

      The  level of significance \alpha = 0.05

 Generally the null hypothesis  is  H_o  :  \mu_1 - \mu_2  = 0

                  the alternative hypothesis is   H_a  :  \mu_1 - \mu_2 >  0

Generally the sample mean for the age of  cars is mathematically represented as

        \= x_1 = \frac{\sum x_i }{n}

=>     \= x_1 = \frac{4+ 0+ 8 +11 + \cdots + 8
}{27}

=>     \= x_1 = 5.56

Generally the standard deviation of age of  cars

     \sigma _1  = \sqrt{\frac{\sum (x_i - \= x)^2}{n_1} }

=>  \sigma _1  = \sqrt{\frac{(4 - 5.56)^2 + (0 - 5.56)^2+ (8 - 5.56)^2 + \cdots + 8}{ 27} }

=>  \sigma _1  =  3.88

Generally the sample mean for the age of taxi is mathematically represented as

        \= x_2 = \frac{\sum x_i }{n}

=>     \= x_2 = \frac{8 +8 +0  + \cdots + 4
}{20}

=>     \= x_2 = 5.85

Generally the standard deviation of age of  taxi

\sigma _2  = \sqrt{\frac{\sum (x_i - \= x)^2}{n_1} }

=>  \sigma _2  = \sqrt{\frac{(8 - 5.85)^2 + (8 - 5.85)^2+ (0 - 5.85)^2 + \cdots + 8}{ 20} }

=>  \sigma _2  = 2.83

Generally the test statistics is mathematically represented as

   t = \frac{(\= x_ 1 - \= x_2 ) - 0}{\sqrt{\frac{\sigma^2_1}{n_1}  + \frac{\sigma^2_2}{n_2} }  }

=> t = \frac{(5.56 - 5.85 ) - 0}{\sqrt{\frac{(3.88)^2}{27}  + \frac{(2.83)}{20} }}  

=> t = -0.30  

Generally the degree of freedom is mathematically  represented as

   df =  n_1 + n_2 -2

    df =  27 +  20 -2

    df =  45

From the t distribution table  the P(t >  t ) at the obtained degree of freedom = 45 is  

   P(t >  -0.30 ) = 0.61722067

So  the  p-value  is

    p-value  =  P(t >  T) =  0.61722067

From the obtained values we see that the  p-value  >  \alpha hence we fail to reject the null hypothesis

Hence the there is no sufficient evidence to support the claim that the mean age of the cars is greater than that of taxi

5 0
3 years ago
I need Help plsssss!!!!!
laiz [17]

Answer:

2x - 3

x - 9

Step-by-step explanation:

The root of a problem is the x value that makes the equation equal to zero.

If the factored form of the equation is (2x-3)(x-9) that means if either 2x - 3 or x - 9 is equal to zero, the entire equation will equal zero, because zero times any number is equal to zero.  

Therefore you must solve for (2x-3)=0 and (x-9)=0

4 0
3 years ago
Can y’all help me pls
krok68 [10]

Answer:

2. The change in expected height for every one additional centimeter of femur length.

Step-by-step explanation:

<u>1. The expected height for someone with a femur length of 65 centimeters.</u>

<em>Doesn't make sense, that would be height value when centimeters = 65.</em>

<u>2</u><u><em>. </em></u><u>The change in expected height for every one additional centimeter of femur length.</u>

<em>Makes sense, for every increase in one additional centimeter, we can expect the height to be proportional to the slope.</em>

<u>3. The femur length for someone with an expected height of 2.5 centimeters.</u>

<em>Doesn't make sense, the linear relationship relies on the femur length to get the height.</em>

<u>4. The change in expected femur length for every one additional centimeter of height.</u>

<em>Doesn't make sense, again, the linear relationship relies on the femur length.</em>

6 0
2 years ago
<img src="https://tex.z-dn.net/?f=4x%5E%7B2%7D%20%2B4x%2B1%3D0" id="TexFormula1" title="4x^{2} +4x+1=0" alt="4x^{2} +4x+1=0" ali
Arturiano [62]

D=b^2-4ac\\D=4^2-4(4)(1)\\D=16-16\\D=0

Meaning there's only 1 real root, complete the square and you get the answer.

(x+y)^2=x^2+2xy+y^2

We're going to use this formula, so if x² = 4x² then x = 2x

and if y² = 1 then y = 1

Straight to formula

(2x+1)^2=0\\x=-\frac{1}{2}

Because (2x+1)² is basically (2x+1)(2x+1), we get the same value of x.

So the answer is x = -1/2

(When D>0, there are 2 real roots.)

(When D=0, there are only 1 real root.)

(When D<0, there are no real roots, but 2 complex roots.)

8 0
3 years ago
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