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3 years ago

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1. Convert 1365.4 joules into kilocalories.

1 answer:

Hunter-Best [27]3 years ago

3 0

Answer:

1365.4 J = 0.326 kcal

Explanation:

To solve this question, we use the unitary method.

1 Joule = 4184 kcal

According to the above equation, one joule is equivalent to that of 4.184 cal or 4184 kcal.

Joule(J) and kilocalories(kcal) are both units of energy.

$1365.4J=\frac{1365.4}{4184}kcal=0.326kcal$

Therefore, the answer is 0.326 kcal.

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From the list of substances, identify each as a strong acid, strong base, or neither a strong acid nor a strong base.

Dafna11 [192]

Answer:

HNO3 is a strong acid

HCl is also a strong acid

NaCl is a salt so it is neither a strong acid nor a strong base

Ca(OH)3 is a strong base

Explanation:

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2 years ago

What is the symbol of a ion with a 22 protons, 34 neutrons, and 18 electrons

Dominik [7]

Well knowing the number of protons, you can find what the element is, which is Ti = titanium. Then to find the charge, simply subtract 22 and 18 which is +3.

Find the mass number by adding 22 and 34 = 56.

56. +3
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3 years ago

How many hydrogen atoms are in 89.5 g of<br> C6H6 ?<br> Answer in units of atoms.

Elodia [21]

Solution :

Molar mass of $C_6H_6$ is :

M = 6×12 + 6×1 g

M = 78 g

78 gram of $C_6H_6$ contains $6.022 \times 10^{23}$ molecules.

So, 89.5 gram of $C_6H_6$ contains :

$n = 6.022 \times 10^{23} \times \dfrac{89.5}{78}\\\\n = 6.91 \times 10^{23}$

Now, from the formula we can see that one molecule of $C_6H_6$ contains 2 hydrogen atom . So, number of hydrogen atom are :

$h = 2\times 6.91 \times 10^{23}\\\\h = 1.38 \times 10^{22}\ atoms$

Hence, this is the required solution.

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3 years ago

plz, help me Lisa’s doctor tells her that she needs to eat more foods that contain calcium to maintain her bone health. What cou

andriy [413]

Answer:

Deficiency of calcium which means that her body will take calcium from her bones which results in weakening of bones. (osteoporosis)

Explanation:

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3 years ago

In the laboratory, a general chemistry student measured the pH of a 0.529 M aqueous solution of phenol (a weak acid), C6H5OH to

Artyom0805 [142]

Answer:

The dissociation constant of phenol from given information is $9.34\times 10^{-11}$ .

Explanation:

The measured pH of the solution = 5.153

$C_6H_5OH\rightarrow C_6H_5O^-+H^+$

Initially c

At eq'm c-x x x

The expression of dissociation constant is given as:

$K_a=\frac{[C_6H_5O^-][H^+]}{[C_6H_5OOH]}$

Concentration of phenoxide ions and hydrogen ions are equal to x.

$pH=-\log[x]$

$5.153=-\log[x]$

$x=7.03\times 10^{-6} M$

$K_a=\frac{x\times x}{(c-x)}=\frac{x^2}{(c-x)}=\frac{(7.03\times 10^{-6} M)^2}{ 0.529 M-7.03\times 10^{-6} M}$

$K_a=9.34\times 10^{-11}$

The dissociation constant of phenol from given information is $9.34\times 10^{-11}$ .

4 0

3 years ago