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anygoal [31]
3 years ago
8

How many hydrogen atoms are in 89.5 g of C6H6 ? Answer in units of atoms.

Chemistry
1 answer:
Elodia [21]3 years ago
8 0

Solution :

Molar mass of C_6H_6 is :

M = 6×12 + 6×1 g

M = 78 g

78 gram of C_6H_6 contains 6.022 \times 10^{23} molecules.

So, 89.5 gram of C_6H_6 contains :

n = 6.022 \times 10^{23} \times \dfrac{89.5}{78}\\\\n = 6.91 \times 10^{23}

Now, from the formula we can see that one molecule of C_6H_6 contains 2 hydrogen atom . So, number of hydrogen atom are :

h = 2\times 6.91 \times 10^{23}\\\\h = 1.38 \times 10^{22}\ atoms

Hence, this is the required solution.

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Calculate the number of atoms of each element. 2,6,15,3,8,5?
katen-ka-za [31]

Answer:

P 6 atoms

O 15 atoms

Explanation:

P = 2×3= 6

O = 5×3= 15

6 0
3 years ago
The correct mathematical expression for finding the molar solubility (s) of calcium phosphate is
GalinKa [24]

Answer is: The molar solubility of calcium phosphate is 108s⁵ = Ksp.

<span> Balanced chemical reaction: Ca</span>₃(PO₄)₂(s) → 3Ca²⁺(aq) + 2PO₄³⁻(aq).<span>
[Ca²</span>⁺] = 3s(Ca₃(PO₄)₂) = 3s.<span>
[PO</span>₄³⁻] = 2s.<span>
Ksp = [Ca²</span>⁺]³ · [PO₄³⁻]².<span>
Ksp = (3s)³ · (2s)².
Ksp = 108s</span>⁵.

s = ⁵√(Ksp ÷ 108).

6 0
3 years ago
A package of chocolate instant pudding contains 2640 mg of sodium. how many grams of sodium are in the pudding?
alexgriva [62]

Answer:

2.640

Explanation:

Rounding to the nearest whole number would be 3 if that is needed.

4 0
1 year ago
The equilibrium of 2H 2 O(g) 2H 2 (g) + O 2 (g) at 2,000 K has a Keq value of 5.31 x 10-10. What is the Keq expression for this
maks197457 [2]
Answer is: Keq expression for this system is Keq = <span>[O</span>₂<span> ]</span> · [H₂<span>]</span>² ÷  [H₂O<span>]</span>².<span>
Chemical reaction: 2H</span>₂O(g) ⇄ O₂(g) + 2H₂(g).
The equilibrium constant<span> (Keq) is a ratio of the concentration of the products (in this reaction oxygen and hydrogen) to the concentration of the reactants (in this reaction water).</span>
7 0
4 years ago
What mass of ammonia can be produced if 13.4 grams of nitrogen gas reacted ?
aivan3 [116]

Answer:

If 13.4 grams of nitrogen gas reacts we'll produce 16.3 grams of ammonia

Explanation:

Step 1: Data given

Mass of nitrogen gas (N2) = 13.4 grams

Molar mass of N2 = 28 g/mol

Molar mass of NH3 = 17.03 g/mol

Step 2: The balanced equation

N2 + 3H2 → 2NH3

Step 3: Calculate moles of N2

Moles N2 = Mass N2 / molar mass N2

Moles N2 = 13.4 grams / 28.00 g/mol

Moles N2 = 0.479 moles

Step 4: Calculate moles of NH3

For 1 mol N2 we need 3 moles H2 to produce 2 moles NH3

For 0.479 moles N2 we'll produce 2*0.479 = 0.958 moles

Step 5: Calculate mass of NH3

Mass of NH3 = moles NH3 * molar mass NH3

Mass NH3 = 0.958 moles * 17.03 g/mol

Mass NH3 = 16.3 grams

If 13.4 grams of nitrogen gas reacts we'll produce 16.3 grams of ammonia

3 0
3 years ago
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