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tangare [24]
3 years ago
5

HURRY ILL MARK BRAINLIEST

Chemistry
1 answer:
Romashka-Z-Leto [24]3 years ago
7 0
I’m confused on what you have to do
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Chemical Equations
vagabundo [1.1K]

Answer:

0.712 moles of NO₂ are formed.

Explanation:

First, we need to write the balanced equation:

2 N₂O₅(g) ⇄ 4 NO₂(g) + O₂(g)

From the balanced equation, we can see the relationship between the moles of N₂O₅ and the moles of NO₂. Every 2 moles of N₂O₅ that react, 4 moles of NO₂ are formed. Let us apply this relationship to the information given by the problem (0.356 moles of N₂O₅):

0.356molN_{2}O_{5}.\frac{4molNO_{2}}{2molN_{2}O_{5}} =0.712molNO_{2}

3 0
3 years ago
The pressure on a 200 milliliter sample of CO2 (g) at constant temperature is increased from
balu736 [363]

The answer for the following problem is mentioned below.

  • <u><em>Therefore the final volume of the gas is 100 ml.</em></u>

Explanation:

 Given:

Initial pressure (P_{1}) = 600 mm of Hg

Final pressure (P_{2}) = 1200 mm of Hg

Initial volume (V_{1}) = 200 ml      

To find:

Final volume (V_{2})

We know;

According to the ideal gas equation,

    P × V = n × R × T

Where;

P represents the pressure of the gas

V represents the volume of the gas

n represents the no of moles of the gas

R represents the universal gas constant

T represents the temperature of the gas

So,

 From the above mentioned equation,

        P × V = constant

\frac{P_{1} }{P_{2} } = \frac{V_{1} }{V_{2} }

Where,

(P_{1}) represents the initial pressure of the gas

(P_{2}) represents the final pressure of the gas

(V_{1})  represents the initial volume of the gas

(V_{2})  represents the final volume of the gas

So;

\frac{600}{1200} = \frac{V_{2} }{200}    

V_{2} = 100 ml

<u><em>Therefore the final volume of the gas is 100 ml.</em></u>                                                                                                                                                                              

5 0
4 years ago
Which represents the self-ionization of water at 25°C? H2O + H2O 2H2 + O2 H2O + H2O H2O2 + H2 H2O + H2O 4H+ + 2O2- H2O + H2O H3O
Vitek1552 [10]
The fourth answer is correct 
H20 + H20  H30 + 0H-
6 0
3 years ago
Read 2 more answers
How much heat is required to vaporize 43.9 g of acetone at its boiling point?
bogdanovich [222]
The heat required to vaporize 43.9 g  of acetone  at its boiling point is calculated as  below

 the heat of vaporization of acetone at its boiling  point is  29.1 kj/mole

find the moles of  acetone = mass/molar mass
= 43.9g /58 g/mol =0.757 moles

heat (Q) = moles x heat of vaporization

= 29.1 kj/mole  x 0.757 moles = 22.03 kj
5 0
3 years ago
Read 2 more answers
Propane (c3h8) is burned in oxygen to produce carbon dioxide and water. the heat of combustion of propane is -2012 kj/mole. how
Olegator [25]
C_{3} H_{8} + 5 O_{2} ---\ \textgreater \  3CO_{2}  +4H_{2}O    (-2012 \frac{kJ}{mol} )&#10;&#10;&#10;3 mol                10 mol&#10;&#10;&#10;C_{3}H_{8} is /excess /reactant&#10;&#10;because 3 mol propane require 15 mol oxygen (by reaction)&#10;&#10;5 mol oxygen ---1 mol propane, so&#10;&#10;10 mol oxygen ---2 mol propane&#10;&#10;Only 2 mole propane will be burned,&#10;&#10;so &#10;&#10;2012 ( kJ/mol)*2 mol =4024 KJ heat will be given off&#10;&#10;Correct answer is number 4.&#10;&#10;&#10;
5 0
3 years ago
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