Explanation:
The given data is as follows.
= 211 nm, 
l = 1 cm, 7% < Transmittance < 85%
Suppose the aqueous solution follows Lambert-Beer's law. Therefore,
Absorbance = 
Hence, for 7% transmittance the value of absorbance will be as follows.
Absorbance = 
= 1.155
For 85% transmittance the value of absorbance will be as follows.
Absorbance = 
= 0.07058
According to Lambert-Beer's law.
A = 
where, A = absorbance
= molar extinction coefficient
C = concentration
Therefore, concentration for 7% absorbance is as follows.

= 
= 
= 0.187 mmol/L
Concentration for 85% absorbance is as follows.

= 
= 
= 0.01144 mmol/L
Thus, we can conclude that linear range of phenol concentration is 0.01144 mmol/L to 0.187 mmol/L.
Answer:a) 0.1 mole. b) 4g. c) 2% d) 196 mL
Explanation: in 200mL , 0.1mole
mw NaOH = 40g/mol —> 4g in 0.1 mole
4g in 200mL so 2g in 100mL
density NaOH = 1g/mL so if 4g in 200 mL, 4mL , 196 mL water
Answer:
It's true :) Hope that helps