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Neporo4naja [7]
4 years ago
15

Suma divizorilor naturali ai numărului 15

Mathematics
1 answer:
xenn [34]4 years ago
3 0
Divizorilor naturali ai numărului 15 es 3 y 5. Suma de 3 y 5 es 8.
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<em> </em><em> </em><em> </em><em> </em><em> </em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em>here's</em><em> your</em><em> solution</em>

<em> </em><em> </em><em> </em><em>=</em><em>></em><em> </em><em>perpendicular</em><em> </em><em>=</em><em> </em><em>2</em><em>4</em>

<em> </em><em> </em><em>=</em><em>></em><em> </em><em>base </em><em>=</em><em> </em><em>7</em>

<em> </em><em> </em><em>=</em><em>></em><em> </em><em>hypotenuse</em><em> </em><em>=</em><em> </em><em>?</em>

<em> </em><em> </em><em>=</em><em>></em><em> </em><em>firstly</em><em> </em><em>we </em><em>need</em><em> to</em><em> find</em><em> </em><em>hypotenuse</em><em> </em>

<em> </em><em>=</em><em>></em><em> </em><em> </em><em>h^</em><em>2</em><em> </em><em>=</em><em> </em><em>p^</em><em>2</em><em> </em><em>+</em><em> </em><em>b^</em><em>2</em>

<em> </em><em> </em><em>=</em><em>></em><em> </em><em>h</em><em>^</em><em>2</em><em> </em><em>=</em><em> </em><em>2</em><em>4</em><em>^</em><em>2</em><em> </em><em>+</em><em> </em><em>7</em><em>^</em><em>2</em>

<em> </em><em> </em><em>=</em><em>></em><em> </em><em>h^</em><em>2</em><em> </em><em>=</em><em> </em><em>5</em><em>7</em><em>6</em><em> </em><em>+</em><em> </em><em>4</em><em>9</em>

<em> </em><em> </em><em>=</em><em>></em><em> </em><em>h^</em><em>2</em><em> </em><em>=</em><em> </em><em>6</em><em>2</em><em>5</em>

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<em>hope</em><em> it</em><em> helps</em>

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