The abscissa of the ordered pair, that is the x-coordinate, is equal to 1 and the ordinate, the y-coordinate, is equal to -1. In the cartesian plane, this point lies in the fourth (IV) quadrant. The standard position of the angle is that which has one of its side is in the x-axis.
Solve for the hypotenuse of the right triangle formed.
h = sqrt((-1)² + (1)²) = √2
Below items show the calculation for each of the trigonometric functions.
sin θ = opposite/hypotenuse = y/h = (-1)/(√2) = -√2/2
cos θ = adjacent/hypotenuse = x/h = (1)/√2 = √2/2
tan θ = opposite/adjacent = y/x = -1/1 = -1
Answer: Never
Step-by-step explanation:
In a triangle the 3 angles have to add up to 180 degrees and if there are 2 90 degree angles the sum is 180 which is not possible to add more degrees without going over
Answer: has a maximum
the maximum is 11
Step-by-step explanation:
f(x)= -5x^2-10x+6
the function f(x)= ax^2+bx+c=0 has a<0 so the equation has a maximum
I know V has the coordonate x=-b/2a, and y=-(b^2-4ac)/4a
b^2-4*a*c= (-10)^2-4*(-5)*6=100+120=220
so -b/2a=-(-10)/-2*5=+10/-10=-1 and
-(b^2-4ac)/4a=-220/4*(-5)=-220/-20=22/2=11
so V( -1, 11)
and the maximum is 11
