Answer:
B, Work with the math instructors to create a list of students currently taking a math class. Randomly select
Step-by-step explanation:
Let's think of each scenario at a time.
(A) We select 100 students enrolled in college randomly that should be fine because we are taking only students that can take classes. this rules out faculty members and any other persons but also there may be students that will never take any math course as part of their study plan, this is ruled out on that basis.
(B)if we take 100 students from the list of math instructor, that will ensure that we have taken students that are taking math class now, and math is part of their study plan, seems fine.
(C) visiting cafeteria randomly on multiple days will give us random persons that may not even be enrolled in university. this can be ruled out on that basis.
(D)Ten class at random and surveying each student in every class will make sampling size large or small depending on students enrolled in each of the class this will not give us reliable results.
We can conclude that (B) is the beast method for obtaining reliable results.
Answer:
3.
Step-by-step explanation:
Find the midpoint of BC:
midpoint = (-1+5)/2, (2-2)/2 = (2, 0).
The slope of BC = (2 - -2) / (-1-5) = -2/3.
Find the equation of the right bisector of BC:
The slope = -1 / -2/3 = 3/2.
y-y1 = m(x-x1)
y - 0 = 3/2(x - 2)
y = 3/2x - 3.
Now find the equation of the median through C:
The midpoint of AB = (1 - 1)/2, (4+2)/2
= (0, 3).
The equation of the median:
The slope = (-2-3) / (5-0)
= -1.
The equation is:
y - 3 = -1(x - 0)
y -3 = -x.
Now we find the point of intersection by solving the 2 equations:
y - 3 = -x
y = 3/2x - 3
y = -x + 3
So:
3/2x - 3 = -x + 3
3/2x + x = 6
5/2 x = 6
x = 12/5.
y = -12/5 + 3
= -12/5 + 15/5
= 3/5.
The sum of the coordinates = 12/5 + 3 /5
= 15/5
= 3.
