Answer:
x>1
Step-by-step explanation:
jayfeather friend me
Answer:
0,-8
-6,0
Step-by-step explanation:
Given that JKLM is a rhombus and the length of diagonal KM=10 na d JL=24, the perimeter will be found as follows;
the length of one side of the rhombus will be given by Pythagorean theorem, the reason being at the point the diagonals intersect, they form a perpendicular angles;
thus
c^2=a^2+b^2
hence;
c^2=5^2+12^2
c^2=144+25
c^2=169
thus;
c=sqrt169
c=13 units;
thus the perimeter of the rhombus will be:
P=L+L+L+L
P=13+13+13+13
P=52 units
Answer:
Step-by-step explanation:
combine like terms
-7x + 3x - 15y - 2y
-4x - 17y
Answer:
6
Step-by-step explanation:
