Ask question

Ask question

All categories

2 years ago

15

Dawn Lingua bought three yards of cloth to make some curtains. The cloth was on sale for $2.25 per yard. How much did Dawn pay f

or the cloth if the sales tax was 5%?

1 answer:

AURORKA [14]2 years ago

7 0

$2.25 <span>$7.0875</span>
$2.25
$2.25
---------
$6.75
x Tax 5%
$7.0875

You might be interested in

You walk 2 miles in 1/2 an hour at that rate how long will it take to walk 3 miles?

In-s [12.5K]

Answer:45 minutes

Step-by-step explanation:since you walk 4 miles an hour in half of one you walk 2

6 0

2 years ago

Jake wants to know if his basketball team has gotten better. Last season, Jake's team won 10 out of 20 games. This season, his t

kifflom [539]

Answer:

This season

Step-by-step explanation:

Lowest Common Multiple (LCM) of 20 and 25 = 100

10/20 * 5/5 = 50/100 = 5/10

15/25 * 4/4 = 60/100 = 6/10

5/10 < 6/10

7 0

1 year ago

Solve for x.<br> 9(x - 2) = 18<br> o x=0<br> X = 16/9<br> x = 20/9

iragen [17]

Answer:

x = 4

Step-by-step explanation:

9(x - 2) = 18

9x - 18 = 18

9x = 18 + 18

9x = 36

x = 36/9

x = 4

5 0

2 years ago

Read 2 more answers

A floor is made up of 20 triangular tiles, each with sides 40 cm, 24 cm and 32 cm. Find the cost of polishing the floor at the r

pochemuha

Answer:

$15360\,\,rupees$

Step-by-step explanation:

Let sides of the triangle be $a,b,c$

$a=40\,,\,b=24\,,\,c=32$

Semi-perimeter (s) = $\frac{a+b+c}{2}$

$=\frac{40+24+32}{2}\\ =\frac{96}{2}\\=48$

Area of one tile $=\sqrt{s(s-a)(s-b)(s-c)}$

$=\sqrt{48(48-40)(48-24)(48-32)}\\ =\sqrt{48(8)(24)(16)}\\ =\sqrt{147456} \\=384\,\,cm^2$

So,

Area of 20 tiles $=20(384)=7680\,\,cm^2$

Cost of polishing the floor at the rate of 2 rupees per sq.cm = $7680(2)=15360\,\,rupees$

7 0

2 years ago

A particle, initially at rest, moves along the x-axis such that its acceleration at time t > 0 is given by a(t) = 6cos(t). At

Rom4ik [11]

a. By the fundamental theorem of calculus, the velocity function is

$v(t)=v(0)+\displaystyle\int_0^ta(u)\,\mathrm du$

The particle starts at rest, so $v(0)=0$ , and we have

$v(t)=\displaystyle\int_0^t6\cos u\,\mathrm du=6\sin u\bigg|_0^t=6\sin t$

Then the position function is

$x(t)=\displaystyle x(0)+\int_0^tv(u)\,\mathrm du$

with $x(0)=6$ , so

$x(t)=6+\displaystyle\int_0^t6\sin u\,\mathrm du=6-6\cos u\bigg|_0^t=12-6\cos t$

b. The particle is at rest whenever $v(t)=0$ ; this happens for

$6\sin t=0\implies \sin t=0\implies t=n\pi$

where $n$ is any integer.

3 0

2 years ago