Astronomers think most galaxy interactions took place at redshifts of greater than 1 because

The density of a material in CGS system of units is 4g cm-³. In a system of units in which unit of length is 10 cm and unit of m

butalik [34]

$\sf\underline{Solution:}$

Here , the density of the material is 4g cm³ but it is not given in CGS system.

$\sf{As\:we\:know\:that:}$

$\sf\bold{Density=}$ $\sf\dfrac{Mass}{Volume}$

$\space$

$\sf{Now,according \: to \:the\:question:}$

$\sf\small{Density\:of\:the\:material=4}$ $\sf\dfrac{g}{cm^2}$

$\space$

$\sf{It\:is\:given\:that:}$

In the system of units the mass is 100gram.

$\space$

Hence,

$\sf{The\:mass\:unit\:for\:4g=}$ $\sf\dfrac{4}{100}$ $\sf{units}$

$\space$

In the system of units,the length is 10cm.

Henceforth,

$\sf\small{The\:length \:for\:1cm\:units=}$ $\sf\dfrac{1}{10}$ $\sf{units}$

$\space$

☆ Substitute the required values in the given formula-

$\sf\purple{Density=}$ $\sf\dfrac\purple{Mass}\purple{volume}$

$\space$

$\sf\underline\bold{Density\:of\:the\:material:}$

= $\sf\dfrac{4/100}{1/10^3}$ $\sf\bold{units}$

$\space$

= $\sf\dfrac{4/100}{1/1000}$ $\sf\bold{units}$

$\space$

= $\sf\dfrac{4000}{100}$ $\sf\bold{units}$

$\space$

$\sf\underline\bold\blue{=40\:units}$

$\sf\small{Therefore,option\:2nd\:is\:correct!}$

_______________________________

6 0

3 years ago

A parallel-plate capacitor is charged by connecting it to a battery. If the battery is disconnected and then the separation betw

TEA [102]

Answer:

The charge stored in the capacitor will stay the same. However, the electric potential across the two plates will increase. (Assuming that the permittivity of the space between the two plates stays the same.)

Explanation:

The two plates of this capacitor are no longer connected to each other. As a result, there's no way for the charge on one plate to move to the other. $Q$ , the amount of charge stored in this capacitor, will stay the same.

The formula $\displaystyle Q = C\, V$ relates the electric potential across a capacitor to:

$Q$ , the charge stored in the capacitor, and
$C$ , the capacitance of this capacitor.

While $Q$ stays the same, moving the two plates apart could affect the potential $V$ by changing the capacitance $C$ of this capacitor. The formula for the capacitance of a parallel-plate capacitor is:

$\displaystyle C = \frac{\epsilon\, A}{d}$ ,

where

$\epsilon$ is the permittivity of the material between the two plates.
$A$ is the area of each of the two plates.
$d$ is the distance between the two plates.

Assume that the two plates are separated with vacuum. Moving the two plates apart will not affect the value of $\epsilon$ . Neither will that change the area of the two plates.

However, as $d$ (the distance between the two plates) increases, the value of $\displaystyle C = \frac{\epsilon\, A}{d}$ will become smaller. In other words, moving the two plates of a parallel-plate capacitor apart would reduce its capacitance.

On the other hand, the formula $\displaystyle Q = C\, V$ can be rewritten as:

$V = \displaystyle \frac{Q}{C}$ .

The value of $Q$ (charge stored in this capacitor) stays the same. As the value of $C$ becomes smaller, the value of the fraction will become larger. Hence, the electric potential across this capacitor will become larger as the two plates are moved away from one another.

3 0

3 years ago

Two models of the same compound are shown. In what way is Model B better than Model A? Model B shows the types of elements in th

irina [24]

Answer: Option (B) is the correct answer.

Explanation:

When model B shows three dimensional shape of the molecule then it becomes easier to visualize the exact shape or geometry of the molecule as we get to know how atoms are bonded together.

Therefore, with the help of this it would be easy to know the hybridization of molecule. Basically, we will get to know the type of molecule represented by model B.

Thus, we can conclude that the statement Model B shows the three-dimensional shape of the molecule, but Model A does not represents Model B better than Model A.

6 0

3 years ago

Read 2 more answers

Calculate the pressure in SI unit when a force of 100 dyne acts on area of 0.02cm²

Andru [333]

Answer:

500 Pa

Explanation:

Convert given units to SI:

100 dyne = 0.001 N

0.02 cm² = 2×10⁻⁶ m²

Pressure = force / area

P = 0.001 N / (2×10⁻⁶ m²)

P = 500 Pa

7 0

3 years ago

An student writes a bird that is divining for prey has speed of _ 10m/s what is wrong with the statement.

Anika [276]

Answer:

The description including its issue is summarized throughout the clarification portion below.

Explanation:

Speed would be a measurement of size. Which has only significance and therefore no path or guidance. Student says acceleration of -10m/s, therefore this assumption is incorrect because this same negative correlation indicates the path.
In reality, this same participant defined the speed (which seems to have two very different motion of an object).

4 0

3 years ago