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Naya [18.7K]
3 years ago
11

PLEASE HELP PHYSICS!!!!! WILL MARK BRAINLIEST IF CORRECT!!!!

Physics
2 answers:
denis-greek [22]3 years ago
8 0

Elapsed Time=Time(final)-Time(initial)

The elapsed time for Trial B is 3 seconds.


Average speed=distance traveled/elapsed time

The average speed for Trial B is 1.3 m/s.

hope i helped

zaharov [31]3 years ago
6 0

a) Elapsed time for trial B: 3.0 s

Explanation:

The elapsed time is defined as the difference between the final time and the initial time:

t_{elapsed} = t_{final}-t_{initial}

For trial B, the final time is 4.5 s, while the initial time is 1.5 s, therefore the elapsed time is

t_{elapsed} = 4.5 s-1.5 s=3.0 s


b) Average speed for trial B: 1.3 m/s

Explanation:

The average speed is given by the distance traveled divided by the elapsed time:

v=\frac{d}{t_{elapsed}}

For trial B, the distance traveled is d=4.0 m, while the elapsed time is t=3.0s, therefore the average speed is

v=\frac{4.0 m}{3.0 s}=1.3 m/s

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(b) 25 s

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\alpha = \frac{\omega_f - \omega_i}{t}

If we re-arrange it for t, we get:

t = \frac{\omega_f - \omega_i}{\alpha}

where here we have

\omega_i = 2000 rad/s is the initial angular speed

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