Question

PLEASE HELP PHYSICS!!!!! WILL MARK BRAINLIEST IF CORRECT!!!!

Answer 1

Elapsed Time=Time(final)-Time(initial)

The elapsed time for Trial B is 3 seconds.

Average speed=distance traveled/elapsed time

The average speed for Trial B is 1.3 m/s.

hope i helped

Answer 2

a) Elapsed time for trial B: 3.0 s

Explanation:

The elapsed time is defined as the difference between the final time and the initial time:

$t_{elapsed} = t_{final}-t_{initial}$

For trial B, the final time is 4.5 s, while the initial time is 1.5 s, therefore the elapsed time is

$t_{elapsed} = 4.5 s-1.5 s=3.0 s$

b) Average speed for trial B: 1.3 m/s

Explanation:

The average speed is given by the distance traveled divided by the elapsed time:

$v=\frac{d}{t_{elapsed}}$

For trial B, the distance traveled is d=4.0 m, while the elapsed time is t=3.0s, therefore the average speed is

$v=\frac{4.0 m}{3.0 s}=1.3 m/s$