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oksian1 [2.3K]
4 years ago
11

How much force is needed to accelerate a 1,500 kg car at a rate of 7 m/s2?

Physics
1 answer:
Sidana [21]4 years ago
4 0

Newton's 2nd law of motion:   

                       Force = (mass) x (acceleration)
                                         |                 |   
                                 (1,500 kg) x (7 m/s²)  =  10,500 newtons .
                         
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7 0
3 years ago
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Answer:

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Explanation:

If long wings are a dominant trait, that means short wings are recessive. If two short winged flies are crossed, each of their phenotypes are ww. Therefore, each of their offspring also have phenotype ww, or short wings.

7 0
3 years ago
A sample of gold has a volume of 2 cm3 and a mass of 38.6 grams. What would be the density, and three other properties of the sa
lukranit [14]

The density of the gold is calculated to be "19,300 kg/m³".

<u>Explanation:</u>

Given:

Volume = 2cm³

Mass = 38.6 grams.

To Find:

Density of the gold = ?

Solution:

Density is obtained by dividing mass of the sample by its volume and it is given in the units of kg/m³.

Mass in grams is converted into kg as,

1 g = 0.001 kg

38. 6 g = \frac{38.6}{1000} = 0.0386 kg

Now we have to convert cm³ to m³ as,

1 cm³ = 10⁻⁶ m³

2 cm³ = 2 × 10⁻⁶ m³

So Density = \frac{0.0386 k g}{2 \times 10^{-6} m^{3}}=19,300 \mathrm{kg} / \mathrm{m}^{3}

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3 0
3 years ago
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Ronch [10]
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6 0
3 years ago
Suppose our experimenter repeats his experiment on a planet more massive than Earth, where the acceleration due to gravity is g
Ne4ueva [31]

Answer:

C

Explanation:

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- Let acceleration due to gravity @ earth be g = 30 m/s^2

Solution:

- The average time taken for the ball to cover a distance h from chin to ground with acceleration a on massive planet is:

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- Hence, we can see the average time taken by the ball on massive planet is less than that on earth to reach back to its initial position. Hence, option C

7 0
3 years ago
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