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Nata [24]
3 years ago
8

The perimeter of a rectangle swimming pool is 160 feet. The length of the swimming pool is four times its width . Find the dimen

sions of the swimming pool.
Mathematics
2 answers:
IRINA_888 [86]3 years ago
8 0
The length of the swimming pool is 64 feet long, and the width is 16 feet long. So the pool is 64' by16'
Helga [31]3 years ago
3 0
Formula for Perimeter of Rectangle:

P = 2(L + W)

Plug in 160:

160 = 2(L + W)

L = 4W
<span>So we can plug in '4W' for 'L' in the first equation.</span>
<span>160 = 2(L + W)

160 = 2(4W + W)

Combine like terms:

160 = 2(5W)

160 = 10W

Divide 10 to both sides:

W = 16

Now we can plug this back into any of the two equations to find the length.

L = 4W

L = 4(16)

L = 64

So the width is 16, and the length is 64.</span>
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Step-by-step explanation:

m you simply slide the decimal over one space to the left in order to convert from millimeters to centimeters. Have an Awesome day and hope i could help!    :)

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2 years ago
The 100th term in 8, 13, 18,23, 28,...
Lunna [17]

Answer:

The 100th term of the sequence is 503.

Step-by-step explanation:

Given : Sequence 8, 13, 18,23, 28,...

To find : The 100th term in the sequence ?

Solution :

Sequence 8, 13, 18,23, 28,... is the arithmetic sequence

Where, First term is a=8

The common difference is d=13-8=5

The nth term of the sequence is given by a_n=a+(n-1)d

The 100th term is given by,

a_{100}=8+(100-1)5

a_{100}=8+(99)5

a_{100}=8+495

a_{100}=503

The 100th term of the sequence is 503.

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3 years ago
Suppose two days before yesterday was wednesday.what day of the week will be 100 days from today
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3 years ago
The morse code is "FOUR BEFORE DECIMAL" I need help with the math problem and how FOUR BEFORE DECIMAL fits into it
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Step-by-step explanation:

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5 0
2 years ago
Read 2 more answers
HEEEEELP!!!!!!!!!!!!!11 I WILL MARK BRAINLIEST kx-3y=4 4x-5y=7 k is constant and x and y are variables, for what value of k will
Studentka2010 [4]

Answer:

<h2>               A.  ¹²/₅</h2>

Step-by-step explanation:

There is no solution for system of equations:  a_1x+b_1y=c_1\\a_2y+b_2y=c_2

if:     a_1=a_2\quad and\quad b_1=b_2\quad and\quad \bold{c_1\ne c_2}

so first, we we need to transform the equations to the form where the coefficients at y will be the same:

kx-3y=4\\ 4x-5y=7\\\\ (kx-3y)\cdot5=4\cdot5\\ (4x-5y)\cdot3=7\cdot3\\\\ 5kx-15y=20\\ 12x-15y=21

Now we have  b₁=b₂ and c₁≠c₂ so the system has no solution if a₁=a₂

5k = 12

÷5     ÷5

k = ¹²/₅

7 0
3 years ago
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