Answer:
Uhm ...... Anyways ............
Answer:
I got x<equal to -11 or x>equal to4
Step-by-step explanation:
x^2+15x+44=0
(x+4)(x+11)=0(Factor left side of equation)
x+4=0 or x+11=0(Set factors equal to 0)
x=−4 or x=−11
Check intervals in between critical points. (Test values in the intervals to see if they work.)
x<−11(Works in original inequality)
−11<x<−4(Doesn't work in original inequality)
x>−4(Works in original inequality)
Answer:
x<−11 or x>−4
All you need to do is plug in 3 wherever you see an x!
y = 3(3) - 2(3)^2 + 5(3)^3
y = 9 - 2(9) + 5(27)
y = 9 - 18 + 135
y = -9 + 135
y = 126
Hope this helps!
The answer for your question is A
I have actually, but all I did was block the number, as I was not aware that they had any of my details.
