The length of a screw produced by a machine is normally distributed with a mean of 0.55 inches and a standard deviation of 0.01
inches. What percent of screws are between 0.53 and 0.57 inches?
99.7%
68%
95%
100%
2 answers:
The answer is 95 percent.
Find the relation between the range, the standard deviation and the media:
0.57 = 0.55 + 0.02 = 0.55 + 2*0.01 = media + 2* standard deviation
0.53 = 0.55 - 0.02 = 0.55 - 2*0.01 = media - 2 * standard deviation
Then, the desired range is media +/- 2 * standard deviation.
In normally distributed functions, this correspond to 95% confidence interval.
Then, the answer is the third option shown, 95%
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