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3 years ago

How does math relate to electrons and ion formation?

2 answers:

7 0

In order to find the NET nuclear charge from an atom's valence electron to the proton nucleus, you need to do some simple math in order to find the charge.

You would also need to apply math when you need to figure out what the charge on an ion is by either adding or taking away electrons depending on whether it is an anion or cation.

AlladinOne [14]3 years ago

5 0

Answer and explanation;

Ions are formed when an atom looses or gains electrons.

-Ionic charges are created when there is an imbalance of protons and electrons on an atom. Since we can not change the number of protons on the nucleus of an atom, a positively charged ion will be created when there are fewer electrons than protons (in other words when an atom looses electron). A negatively charged ion is formed or created when there are more electrons than protons in an atom (when an atom gains electrons).

-When electron are added, you are adding more negative charge and thus, results in the creation of a negative ion (anion), and when electrons are being lost by an atom, one is removing negative charge, resulting in creation of a positive ion (cation).

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3 years ago

An aqueous solution at 25°C has a OH− concentration of 1.9x10−8M . Calculate the H3O+ concentration. Be sure your answer has the

Papessa [141]

Answer:

= 5.26 × 10^-7 M

Explanation:

We know that;

[H3O+][OH-] = 1 x 10^-14

Therefore;

Given; OH− concentration = 1.9x10^−8 M

Then; [H3O+] = (1 x 10^-14)/[OH-]

= (1 x 10^-14)/(1.9x10^−8)

= 5.26 × 10^-7 M

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3 years ago

Read 2 more answers

Calculate the number of atoms in 2.5 moles of Si.

Ede4ka [16]

Answer:

$\boxed {\boxed {\sf About \ 1.5 * 10^{24} \ atoms \ Si}}$

Explanation:

When converting from moles to atoms, we must use Avogadro's number. This number tells us there are 6.022 * 10²³ atoms in 1 mole. We can multiply this number by the number of moles.

First, we must set up Avogadro's number as a ratio.

$\frac {6.022 \ * 10^{23} \ atoms \ Si }{1 \ mol \ Si}}$

Next, multiply the number of moles by the ratio.

$2.5 \ mol \ Si *\frac {6.022 \ * 10^{23} \ atoms \ Si }{1 \ mol \ Si}}$

When we multiply, the moles of silicon will cancel.

$2.5 * \frac {6.022 \ * 10^{23} \ atoms \ Si }{1}}$

Since the denominator of the fraction is 1, we can cancel it out too.

$2.5 * {6.022 \ * 10^{23} \ atoms \ Si }$

$1.5055 * 10^{24} \ atoms \ Si$

The original measurement (2.5 moles) has 2 significant figures (2 and 5). Therefore we must round to 2 sig figs. For this question, 2 sig figs is the tenth place.

The 0 in the hundredth place tells us to leave the 5 in the tenth place.

$1.5 * 10^{24} \ atoms \ Si$

There are about <u>1.5 * 10²⁴ atoms of silicon.</u>

7 0

2 years ago

Determine the correct metric length of the cockroach in this image

Reika [66]

Answer:

were is the image

Explanation:

7 0

3 years ago

What is the total number of years that must pass before only 25.00 grams of an original 100.0-gram sample of C-14 remains unchan

Karolina [17]

The answer is (3) 11,460 y. For this problem, you must know that the half life of C-14 is 5740 y and that nuclear decay processes are first order reactions (which means that the half life remains constant). For 25.00g to be left of a 100.0g sample, two half life must have elapsed (100*0.5*0.5=25). Each half life is 5730 y, so the total time elapsed is 5730 * 2 = 11,460 y.

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3 years ago

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