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Vitek1552 [10]
3 years ago
5

What is the IUPAC name for the following compound?

Chemistry
1 answer:
djyliett [7]3 years ago
5 0

Answer:

Option a. Benzenecarbonitrile

Explanation:

You are not providing the picture of the compound. However, I manage to find the picture of it, so I'm gonna answer this with the picture. Its attached here at the end.

As for the IUPAC name of this compound, it would be Benzenecarbonitrile, or simply, benzonitrile.

This compound has the molecular formula C₆H₅CN. It receives this name over the other ones, because this is a aromatic cyanide, and aromatic cyanide has nitriles behavior, (Strength of the nitrogen over the carbon), therefore, this group has priority over the whole molecule. As the principal chain is the benzene, the carbonitrile is the radical of the group, and when cyano groups are as radical and not as principal chains, it has a behavior of nitrile, and it's named as nitrile. therefore, option b, cannot be the name.

phenylcyanide is naming the phenyl as radical, but the benzene is the principal group in this compound, and the cyanide is the radical. It happens the same thing with cyanophenyl.

Hope this helps

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State the modern periodic law​
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How many grams are in 4 moles of H2O?​
ivanzaharov [21]

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2 years ago
Calculate the whole-number ratio of staggered to eclipsed conformers that are present at room temperature. Use the Actual G˚ bar
natka813 [3]

Answer:

The ratio of staggered to eclipsed conformers is 134

Explanation:

It is possible to determine the ratio of staggered to eclipsed conformers of a reactant, using the equilibrium:

Staggered ⇄ Eclipsed

Keq = [Eclipsed] / [Staggered]

That means Keq is equal to the ratio we need to find:

Using:

G˚= -RTln Keq

<em>Where G° = -12133.6J/mol</em>

<em>R is gas constant: 8.314J/molK</em>

<em>T is absolute temperature: 298K</em>

<em />

-12133.6J/mol= -8.314J/molK*298K ln Keq

4.8974 = ln Keq

134 = Keq = [Eclipsed] / [Staggered]

<h3>The ratio of staggered to eclipsed conformers is 134</h3>
3 0
3 years ago
What is the mass number of an atom that contains 12 protons, 14 neutrons, and 12 electrons? *
Yuri [45]

The mass number of an atom : 26

<h3>Further explanation</h3>

Given

12 protons, 14 neutrons, and 12 electrons

Required

The mass number

Solution

Inside the atom there are 3 sub-particles, namely protons, neutrons and electrons. Protons and electrons are present in the atomic nucleus while electrons move around the atomic nucleus through energy levels in the atomic shell

Atomic number = number of protons = number of electrons

Mass number = number of protons + number of neutrons

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All elements on the periodic table of elements are
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First 30

Hydrogen

Helium

Lithium

Beryllium

Boron

Carbon

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Oxygen

Fluorine

Neon

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Magnesium

Aluminum

Silicon

Phosphorus

Sulfur

Chlorine

Argon

Potassium

Calcium

Scandium

Titanium

Vanadium

Chromium

Manganese

Iron              

Cobalt

Nickel

Copper

Zinc  

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