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tensa zangetsu [6.8K]
4 years ago
7

Write an equation in slope-intercept form for the line passing through (–1, 10) and (5, 8).

Mathematics
1 answer:
Rus_ich [418]4 years ago
4 0
An equation for the line passing through those points is Y=-1/3x+29/3
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Pepsi [2]
The answer is 9000 g
5 0
3 years ago
Simplify:
Alika [10]
{ e }^{ \ln { \left( B \right) } }{ \left( \frac { 1 }{ R } \right) }^{ -1 }\int { \frac { dA }{ dx } dx } \sqrt { { I }^{ 2 } } \left| -2N+N \right| { \pi }^{ \log _{ \pi }{ \left( L \right) } }\int { \frac { 1 }{ \frac { dx }{ dY } } } dx=\\
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BRAINLY
4 0
3 years ago
+22 + +14 + -10 + +10 + -22 + +14 = n
professor190 [17]

Answer:

Solve for n:

28 = n

Hint: | Reverse the equality in 28 = n in order to isolate n to the left hand side.

28 = n is equivalent to n = 28:

Answer: n = 28

Step-by-step explanation:

6 0
3 years ago
Trevor spent $27 and now has no money left. He had $<br> his purchase.<br> before
7nadin3 [17]

Answer:

Wouldn't it be 27 dollars?

Step-by-step explanation:

6 0
3 years ago
What is the perimeter of triangle ABC?
kkurt [141]

Option B:

The perimeter of ΔABC is 28 units.

Solution:

AD = 5, DC = 6 and AB = 8

AD and AE are tangents to a circle from an external point A.

BE and BF are tangents to a circle from an external point B.

CD and CF are tangents to a circle from an external point C.

<em>Tangents drawn from an external point to a circle are equal in length.</em>

⇒ AD = AE, BE = BF and CD = CF

AE = 5

AE + BE = AB

5 + BE = 8

Subtract 5 from both sides.

BE = 3

BE = BF

⇒ BF = 3

CD = CF

⇒ CF = 6

Perimeter of the polygon = AE + BE + BF + CF + CD + AD

                                         = 5 + 3 + 3 + 6 + 6 + 5

                                         = 28

The perimeter of ΔABC is 28 units.

Option B is the correct answer.

7 0
3 years ago
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