There are four 7's in a standard card. Chance of getting a 7 first is 4/52 = 1/13
There are four queens in a standard card. Chance of getting a queen in the second drawing is 4/51 and chance of getting a queen in the third drawing is 3/50.
Therefore, chance of drawing a seven and two queens is 1/13 x 4/51 x 3/50 = 2/5525
Answer:
7. 8125 l
Step-by-step explanation:
256 km ....... 20l
100 km ...........x l
x = 100×20/256
= 7. 8125 l
Answer:
2/3
Step-by-step explanation:
7/12+1/12=8/12
<u>8</u> / 4 <u>2</u>
12 / 4 3
Final answer 2/3
Answer:
The only difference is that for any positive value of 'x' g(X) and h(X) will be same and for any negative value of 'x' g(x) and h(x) will be different.
Step-by-step explanation:
Given
|x| is modulus of x so modulus makes negative value as psoitive
for example
now we will solve for the above
For 
and
Now for 
and
so for positive value it is same and for negative value it is different
Answer:
<h2>x = 2 </h2><h2>y = - 3</h2><h2>z = - 2</h2>
Step-by-step explanation:
6y - 5z = -8 .......... Equation 1
3z = -6 ................... Equation 2
4x - 3y - 2z= 21...... Equation 3
<u>First solve for z in Equation 2</u>
That's
3z = - 6
Divide both sides by 3
<h3>z = - 2</h3>
Next substitute the value of z into Equation 1 in order to find y
We have
6y - 5(-2) = - 8
6y + 10 = - 8
6y = - 8 - 10
6y = - 18
Divide both sides by 6
<h3>y = - 3</h3>
Finally substitute the values of y and z into Equation 3 to find the value of x
That's
4x - 3(-3) - 2(-2) = 21
4x + 9 + 4 = 21
4x + 13 = 21
4x = 21 - 13
4x = 8
Divide both sides by 4
<h3>x = 2</h3>
So the solutions are
<h3>x = 2 </h3><h3>y = - 3</h3><h3>z = - 2</h3>
Hope this helps you
