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Shalnov [3]
2 years ago
8

Is 6/12 greater than 8/12

Mathematics
2 answers:
DerKrebs [107]2 years ago
8 0
No its not hope i help (:
Sav [38]2 years ago
3 0
\frac{6}{12} is less than \frac{8}{12}. This is because 6/12 and 8/12 already have the same denominators, so we don't need to change em. Now lets look at the numerators:-

6 & 8

Now we will compare these

6 is less than 8

So, 6/12 is less than 8/12.

Hope i helped ya!! 
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Describe the error in finding the median of the data.
damaskus [11]
The error is that the numbers are not in order from least to greatest.
To find the median of data you need to first put the numbers in order from least to greatest.
3 0
2 years ago
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How does the value of log Subscript 2 Baseline 100 compare with the value of Log Subscript 6 Baseline 20?.
attashe74 [19]

You can use the change of base formula to get

\log_2(100) = \frac{\log(100)}{\log(2)} \approx 6.643856

and also

\log_6(20) = \frac{\log(20)}{\log(6)} \approx 1.671950

In general, the change of base formula is

\log_b(x) = \frac{\log(x)}{\log(b)}

8 0
2 years ago
Which expression is equivalent to (cos x)(tan(–x))?
Naya [18.7K]
The tan(-x) is the same thing as -tan(x).  The tangent function is also the same thing as sin(x)/cos(x), right? So let's rewrite that tan in terms of sin and cos:
[cos(x)][tan(-x)] is the same as [cos(x)][ -\frac{sin(x)}{cos(x)}]
We can now cancel out the cos(x), which leaves us only with -sin(x) remaining. So your answer is A.
7 0
3 years ago
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4(x−3)≥56=<br> Please helppppp
pickupchik [31]

Answer:x≥17

Step-by-step explanation:

Let's solve your inequality step-by-step.

4(x−3)≥56

Step 1: Simplify both sides of the inequality.

4x−12≥56

Step 2: Add 12 to both sides.

4x−12+12≥56+12

4x≥68

Step 3: Divide both sides by 4.

4x4≥6

8

4

x≥17

7 0
2 years ago
Find the linear approximation of the function g(x) = 3 1 + x at a = 0. g(x) ≈ Correct: Your answer is correct. Use it to approxi
EleoNora [17]

Answer:

3.296x+3

2.835

3.330

Step-by-step explanation:

g(x) = 3^{1+x}

Let the linear approximation be L(x) at a = 0. This is given by

L(x) = g(a) + g'(a)(x-a)

g'(x) is the derivative of g(x). To find this, we use the form

If f(x) = a^x, then f'(x) =a^x\ln a

By doing this and applying chain rule for the power (which is a function of x), we have

g'(x) = 3^{1+x}\ln 3

Then

g'(0) = 3^{1+0}\ln 3 = 3.296

Also g(0) = 3^{1+0} = 3

Hence L(x) = 3+(x-0)\times3.296 = 3.296x + 3

For 3^{0.95}, 1+x = 0.95 and x=-0.05

Using this in L(x),

3^{0.95} = 3.296(-0.05) + 3 = 2.835

For 3^{1.1}, 1+x = 1.1 and x=0.1

Using this in L(x),

3^{1.1} = 3.296(0.1) + 3 = 3.330

7 0
3 years ago
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