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djverab [1.8K]
3 years ago
9

HELP ASAP PLSS 10 POINTS

Mathematics
2 answers:
iren2701 [21]3 years ago
8 0

Answer:

It's the last one, 2.5

Step-by-step explanation:

Monica [59]3 years ago
5 0
The scale factor is 2.5



let me know if you have any ?s
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3 years ago
Holland added three decimals that made a sum of 2. One of the decimals was 0.34. What are two other decimals Holland could have
ddd [48]
From this question, you can conclude:
1. There are 3 decimal
2. Decimal1 + decimal2+ decimal3= 2
3. The first decimal is 0.34

If you insert the 3rd into 2nd equation, it will become:
0.34+ decimal2+ decimal3= 2
decimal2+ decimal3= 2-0.34
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If there are no rules regarding the second and third decimal, then you can use this both
1.01 + 0.55
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5 0
3 years ago
A post is supported by two wires (one on each side going in oppositedirections) creating an angle of 80° between the wires. The
Vladimir [108]

Using the Sine rule,

\frac{\sin A}{A}=\frac{\sin B}{B}=\frac{\sin C}{C}\begin{gathered} \text{Let A = 14m,} \\ Substituting the variables into the formula,Where the length of the wires are, AP = xm and BP = ym[tex]\begin{gathered} \frac{\sin80^0}{14}=\frac{\sin40^0}{x} \\ \text{Crossmultiply,} \\ x\times\sin 80^0=14\times\sin 40^0 \\ Divide\text{ both sides by }\sin 80^0 \\ x=\frac{14\sin40^0}{\sin80^0} \\ x=9.14m \end{gathered}

Hence, the length of wire AP (x) is 9.14m.

For wire BP (y)m,

Sum of angles in a triangle is 180 degrees,

A^0+P^0+B^0=180^0\begin{gathered} \text{Where A}^0=\text{ unknown,} \\ P^0=80^0\text{ and,} \\ B^0=40^0 \\ A^0+80^0+40^0=180^0 \\ A^0+120^0=180^0 \\ A^0=180^0-120^0 \\ A^0=60^0 \end{gathered}

Using the side rule to find the length of wire BP,

\begin{gathered} \frac{\sin 60^0}{y}=\frac{\sin 80^0}{14} \\ \text{Crossmultiply,} \\ y\times\sin 80^0=14\times\sin 60^0 \\ \text{Didive both sides by }\sin 80^0 \\ y=\frac{14\times\sin 60^0}{\sin 80^0} \\ y=12.31m \end{gathered}

Hence, the length of wire BP (y) is 12.31m

Therefore, the length of the wires are (9.14m and 12.31m).

4 0
1 year ago
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