Answer
N/A
Step-by-step explanation:
lets take a step into our imaginations, ok?
So when you divide, you're basically splitting the numerator into as many parts as the denominator.
imagine you have a chocolate bar, and it has 6 pieces and you want to split it evenly between your 3 friends.
you split it into three equal parts to get 2 pieces per person.
When you divide 0 by 0, your splitting 0 chocolate bars into 0 equal portions, which is why this problem isn't solvable.
Answer:
8.
Denote the equation : y = ax + b
Use the first 2 values of x and y in table:
3a + b = 21
5a + b = 35
Subtract the 2 equations:
=> 2a = 14 => a = 7 => b = 21 - 3 x 7 = 0
=> The solution is y = 7x
9.
Denote the equation : y = ax + b
Use the first 2 values of x and y in table:
5a + b = 17
10a + b = 22
Subtract the 2 equations:
=> 5a = 5 => a = 1 => b = 17 - 5 x 1 = 17 - 5 = 12
=> The solution is y = x + 12
Hope this helps!
:)
B and c, anything with an x^2 term is a quadratic.
Answer:
a , b
Step-by-step explanation:
ans this are the variables
Answer:
Since there are 4 green bars for every 3 red bars and we are trying to find the number of red bars if there are 200 green bars, we can create the ratio:
4
x
:
3
y
Where x is equal to the number of green bars and y
is the number of red bars.
We know the number of green bars is equal to 200, so we can divide it by 4, giving us:
200
/4=50
Then we can solve for y
, the number of red bars.
// Multiple y by 50
3
⋅
50
=
150
So for every 4 green bars, there are 3 red bars.
For every 200 green bars, there are 150 red bars
Step-by-step explanation: