2 years ago

Find the value of 4×10exponent2

2 answers:

6 0

400, PEMDAS tells us exponent before multiplication so you would do 10 x10 because it's to the 2nd power which is 100 then multiply by 4 = 400

Phantasy [73]2 years ago

3 0

The answer is 400 because 4*10 is 40 and 40 to the second power is 400.

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A square with a side length of 5 inches has a area of 25 in<br><br> true or false

Goryan [66]

Answer:

TRUE

Step-by-step explanation:

5 x 5 = 25 in²

6 0

3 years ago

Simplify the problem 2/sqrt 5

AURORKA [14]

2/sqrt 5

by rationalising the denominator,

2/sqrt 5 × sqrt 5/sqrt 5

= 2(sqrt 5)/sqrt 5(sqrt 5)

= 2 sqrt 5/5

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7 0

3 years ago

JUUL Practice & Problem Solving 7.4.PS-10 Question Help Find the area of the polygon in square units. 4 2 e - 8 -6 - 4 - 2 4

V125BC [204]

area formula is

$A=\frac{1}{2}(b1+b2)h$

where:

b1 = small base

b2 = large base

h = height

then solve:

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7 0

1 year ago

find the component equation of the plane which is normal to the vector -2i+5j+k and which contains the point (-10;7;5).

maksim [4K]

Given:

A plane is normal to the vector = -2i+5j+k

It contains the point (-10,7,5).

To find:

The component equation of the plane.

Solution:

The equation of plane is

$a(x-x_0)+b(y-y_0)+c(z-z_0)=0$

Where, $(x_0,y_0,z_0)$ is the point on the plane and $\left< a,b,c\right>$ is normal vector.

Normal vector is -2i+5j+k and plane passes through (-10,7,5). So, the equation of the plane is

$-2(x-(-10))+5(y-7)+1(z-5)=0$

$-2(x+10)+5y-35+z-5=0$

$-2x-20+5y-35+z-5=0$

$-2x+5y+z-60=0$

$-2x+5y+z=60$

Therefore, the equation of the plane is $-2x+5y+z=60$ .

4 0

2 years ago

Is b 90 degrees or do I have to do 180- something

larisa86 [58]

Answer:

90 degrees since its vertical angle

8 0

2 years ago

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