Answer:
i'm not sure but i think its 7,14,21
Step-by-step explanation:
7,14,21
Y = xe^x
dy/dx(e^x x)=>use the product rule, d/dx(u v) = v*(du)/(dx)+u*(dv)/(dx), where u = e^x and v = x:
= e^x (d/dx(x))+x (d/dx(e^x))
y' = e^x x+ e^x
y'(0) = 1 => slope of the tangent
slope of the normal = -1
y - 0 = -1(x - 0)
y = -x => normal at origin
8 feet to 3 yards is in the simplest form
Answer:
1/3 or 0.333333
Step-by-step explanation:
The question talks about a die that was tossed once and we are now asked to find the probability that it is a figure greater than 4
---A die has 6 faces with the numbers 1,2,3,4,5 and 6 one on each of
the six faces.Considering an unbaised die the probability of any of the faces to appear in a single roll is 1/6.
So, P(1)=P(2)=P(3)=P(4)=P(5)=P(6)=1/6
Now that numbers greater than 4 are 5 and 6
So it can be P(5) or P(6)= P(5)+P(6)=2/6 = 1/3 or 0.33333
Answer 1/3 or 0.33333
I aussume the figure is a square and the line √288 is creating 45° angles.
a² + b² = c² a² = b²
2a² = 288
a² = 144
a = 12
Every side is 12in
