All categories

3 years ago

Power is work divided by force

1 answer:

6 0

No, that doesn't work.

[work] divided by [force] = [distance] .

Power = (amount of work done) divided by (time to do the work) .

You might be interested in

In an experiment to test the hypothesis that added phosphate will cause marigolds to produce more blooms, the experimenter has t

Svetlanka [38]

<span>Give an example of a renewable and nonrenewable resource. What are the advantages and disadvantages of each. Which do you think would be a better choice for your community?</span>

5 0

4 years ago

Which model would best demonstrate the role of gravity in the Solar System? O A. a large ball with 8 smaller balls arranged arou

spin [16.1K]

Option D would be the correct answer

7 0

3 years ago

What does it mean when the line on a graph of a distance vs. time changes direction?

tensa zangetsu [6.8K]

The slope of the line ... or the direction it's heading ... is the speed
of whatever is being graphed. So if the line changes direction, it
means that the speed changed at that time.

6 0

3 years ago

A crumb of bread, of mass 0.056 kg, is pulled upon by ants from rival anthills. They exert the following forces: 0.06 N to the n

Valentin [98]

Answer:

a) 1.855m/s^2, 9.71\° to the east-north

b) 0.103N, 9.46° to the west-south

Explanation:

To find the acceleration of the system you can assume that the forces are applied in a xy plane, where force toward north are directed in the +y direction, and forces to the east in the +x direction. BY taking into account the components of the acceleration for each axis you obtain the following systems of equations:

$0.06N-0.06Nsin(45\°)=ma_y\\\\0.08N-0.02N+0.06cos(45\°)=ma_x$

m: mass of the crumb of bread = 0.056kg

you simplify the equations an replace the values of the mass in order to obtain the acceleration components:

$a_y=\frac{0.017N}{0.056kg}=0.313\frac{m}{s^2}\\\\a_x=\frac{0.102N}{0.056kg}=1.829\frac{m}{s^2}$

$\theta=tan^{-1}(\frac{0.313}{1.829})=9.71\°\\\\a=\sqrt{a_x^2+a_y^2}=\sqrt{(1.829)^2+(0.313)^2}\frac{m}{s^2}=1.855\frac{m}{s^2}$

then, the acceleration of the system has a magnitude of 1.855m/s^2 and a direction of 9.71\° to the east-north

The fifth force must cancel both x an y components of the previous net force, that is:

$0.06N-0.06Nsin(45\°)+F_y=0\\\\F_y=-0.017N\\\\0.08N-0.02N+0.06cos(45\°)+F_x=0\\\\F_x=-0.102N\\\\\phi=tan^{-1}(\frac{-0.017}{-0.102N})=9.46\°$

$F=\sqrt{(0.102)^2+(0.017)^2}N=0.103N$

the, the force needed to reach the equilibrium has a magnitude of 0.103N and a direction of 9.46° to the west-south

4 0

3 years ago

If you tried to use a diverging lens as a magnifier by placing the object at the focal point, what type of image would be produc

gladu [14]

Answer:

Upright and smaller than the object

Explanation:

Diverging lens as the name suggests that the rays diverge after the refraction and do not meet in reality. A concave lens is called diverging lens. When there is refraction of light through a concave lens then the light bends away from the principal axis and hence never meet in reality but on tracing the rays backwards the rays appear to meet leading to the formation of a virtual image, which is erect and smaller than the object for an object placed at the focus of the lens.

Similar image is formed for any case when the object is between optical center and infinity.

7 0

4 years ago