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I am Lyosha [343]
3 years ago
5

You are planning a deep space exploration and want to take your cat with you. If your spacecraft achieves a maximum speed of 87%

of the speed of light, how much additional energy is required to bring your cat (during the acceleration only)? Express this quantity in units of Petajoules (1015).Assume you start from zero velocity and your magical cat does not require additional food or litter. The cat weighs 8.5 lbf. Use LaTeX: 3\times10^8 3 × 10 8 m/s for the speed of light.
Physics
1 answer:
Jet001 [13]3 years ago
4 0

Answer:

E = 1.7 10² PJ

Explanation:

Let's use the special relativity relations, specifically the energy of a body is

           E = γ mc²

           γ = \sqrt{ 1 - \frac{v^2}{c^2} }

where m is the rest mass

for that case they tell us that the speed of the body is 87% of the speed of light

                  = 0.87

let's calculate

         γ = \sqrt{1 - 0.87^2}

         γ = 0.49305

let's reduce the mass of the jack to SI units

         W = 8.5 lb (4.448 N / 1lb) = 37.808 N

         W = mg

         m = W / g

         m = 37.808 / 9.8

         m = 3.86 kg

let's look for energy

 

          E = 3.86 (3 10⁸ )² 0.49305

          E = 1.7 10¹⁷ J

let's reduce to take PJ

          E = 1.7 10¹⁷ J (\frac{ 1 PJ}{10^{15} J} )

          E = 1.7 10² PJ

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You are a traffic accident investigator. You have arrived at the scene of an accident. Two cars of equal mass (1,000 kg each) we
kumpel [21]
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3 years ago
I need help on (a)<br> I don't know what equation to use?
Alchen [17]

Impulse = (force) x (length of time the force lasts)

I see where you doodled  (60)(40)  over on the side, and you'll be delighted
to know that you're on the right track !

Here's the mind-blower, which I'll bet you never thought of:
On a force-time graph, impulse (also change in momentum)
is just  the <em>area that's added under the graph during some time</em> !

From zero to 60, the impulse is just the area of that right triangle
under the graph.  The base of the triangle is  60 seconds.  The
height of the triangle is  40N .  The area of the triangle is not
the whole (base x height), but only <em><u>1/2 </u></em>(base x height).

  1/2 (base x height) = 1/2 (60s x 40N) = <u>1,200 newton-seconds</u>

<u>That's</u> the impulse during the first 60 seconds.  It's also the change in
the car's momentum during the first 60 seconds. 

Momentum = (mass) x (speed)

If the car wasn't moving at all when the graph began, then its momentum is  1,200 newton-sec after 60 seconds.  Through the convenience of the SI system of units, 1,200 newton-sec is exactly the same thing as 1,200 kg-m/s .  The car's mass is 3 kg, so after 60 sec, you can write

    Momentum = M x V = (3 kg) x (speed) = 1,200 kg-m/s

and the car's speed falls right out of that. 

From 60to 120 sec, the change in momentum is the added area of that
extra right triangle on top ... it's 60sec wide and only 20N high.  Calculate
its area, that's the additional impulse in the 2nd minute,  which is also the
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8 0
3 years ago
A train car with mass m1 = 515 kg is moving to the right with a speed of v1 = 7.5 m/s and collides with a second train car. The
Anna [14]

Answer:

For the first situation, we first need to find the mass of the second train car.

In order to do that, we apply the conservation of the amount of movement:

515*7.5+m2*0=(m1+m2)*4.8

and we have as a result:

m2 = 289.6875

For the second situation, also we will apply the conservation of the amount of movement:

515*7.5-289.6875*6 = (515+289.6875)*V

and we have as a result:

V = 2.64 (it is moving to the right)

6 0
3 years ago
7. Two workers must pick up bricks that lie on the ground and place them on a worktable. They each
sdas [7]

Answer:

Same work is done by the two workers

The first worker exerts more power than the second person

Explanation:

Work is the product of force and distance moved in the direction of the applied force

Power is the rate at which work is done

7 0
4 years ago
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