Speed can be shown on a graph of position versus time, and acceleration can be shown on a graph of speed versus time.
Answer:
Explanation:
Total frictional force on boxes
= total weight x coefficient of friction
= ( 11 + 7 ) x 9.8 x .02 = 3.53 N
Net force on boxes
= 8.9 - 3.53
= 5.37 N
acceleration = 5.37 /( 11 + 7 )
= 0.3 m / s ²
b ) Let us consider movement of block A ( 11 kg )
acceleration a = .3 m/s²
friction force on block A
11 X 9.8 X .02
= 2.156 N
Net force on block A
8.9 - friction force - reaction force by block B
= 8.9 - 2.156 - F_ c
force = mass x acceleration
8.9 - 2.156 - F_ c = 11 x .3
F_ c = 3.444 N
c )
If force is applied from the side of box B
We consider all forces on box B
frictional force on it
= 7 x 9.8 x .02
= 1.372 N
Net force on it
8.9 - 1.372 - F_c
force = mass x acceleration
= 8.9 - 1.372 - F_c = 7 x .3 ( Acceleration of box B will be the same that is 0.3 m/s² )
F_c = 5.428 N
Answer:
According to the parallelogram law of vector addition if two vectors act along two adjacent sides of a parallelogram(having magnitude equal to the length of the sides) both pointing away from the common vertex, then the resultant is represented by the diagonal of the parallelogram passing through the same common vertex
Explanation:
Ok so Net force is the vector sum of forces acting on a particle or body. The net force is a single force that replaces the effect of the original forces on the particle's motion. It gives the particle the same acceleration as all those actual forces together as described by the Newton's second law of motion.
If 2 children are both pulling on the toy and giving the same amount of Newton’s then nothing would change. If one child is giving more Newton’s then that Child would end up with the toy.
I hope this helped. I didn’t really know how to explain it. <3
Answer:
a) S = 24.4 m/s
b) angle from the +y direction = 28.7°
Explanation:
1) Data
Vy = 21.4 m/s = constant
Vy,o = 0
Ax = 0.301 m/s²
t = 38.9 s
a) V = ?
b) angle=?
2) Formulas
i) Vy = constant = Vy,o
ii) Vx = Vx,o + Ax t = 0 + Ax t = Ax t
3) Solutions
a) speed
t = 38.9 s and Vx,o = 0.301 m/s² ⇒ Vx = 0.301 m/s² × 38.9s = 11.7 m/s
V² = Vx² + Vy² = (11.7 m/s)² + (21.4m/s)² = 594.85 m² / s²
⇒ V = 24.39 m/s
b) angle measured from the +y direction
tan (angle) = Vx/Vy = 11.7 m/s / 21.4 m/s = 0.5467
angle = arctan(0.5467) ≈ 28.7°