The final velocity of the 14 kg object is 1.6 m/s in the same direction
Explanation:
We can solve this problem by using the law of conservation of momentum: the total momentum of the system must be conserved before and after the collision. Therefore, we can write

where:
is the mass of the first object
is the initial velocity of the first object
is the final velocity of the first object
is the mass of the second object
is the initial velocity of the second object
is the final velocity of the second object
Re-arranging the equation and substituting the values, we find:

And the direction is the same as the initial direction, since it has the same sign.
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Answer:
The magnitude of the acceleration of the 19 kg block is 1.414 m/s²
Explanation:
From Newton's second law of motion;

where;
m is the mass of the objects involved, kg
a is the acceleration of the object, m/s²
different forces on the block and string
⇒force due to 15 kg block
=mgcosθ = 15×9.8×cos20 = 15×9.8×0.9396
= 138.12 N
⇒Tensional Force on 19 kg mass:
T = mg = 19×9.8 = 186.2 N

186.2 - 138.12 = a(15+19)
48.08 = a(34)
a = 48.08/34
a = 1.414 m/s²
Therefore, the magnitude of the acceleration of the 19 kg block is 1.414 m/s²
Answer:
right
Explanation:
think of a compass theres N.E.S.W north, east, south, west
That’s kinda messed up ⬆️
Protons are the representative particles of elements, ionic compounds, and covalent compounds.