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sweet [91]
3 years ago
11

C. A helium atom has a diameter of approximately 9.8 • 10-11 meters. What is the diameter of a helium atom in nanometers? Given

unit: ____________ Answer unit: ____________ Solution: ____________
Physics
1 answer:
Studentka2010 [4]3 years ago
4 0

1\ nm = 10^{-9} m\\\\1\ m =\frac{1\ nm}{10^{-9}}

Since the diameter of helium atom is approximately 9.8\times 10^{-11}\ m, therefore the diameter of helium atom in nano meter,

9.8\times 10^{-11}\ m=9.8\times 10^{-11} \times\frac{1\ nm}{10^{-9}}=0.098\ nm

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If you set up set up your account to use a security key, can you still get in without having the physical key ?
butalik [34]

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2 years ago
Question 14 (1 point)
Karo-lina-s [1.5K]

Answer:

car travel

precipitation

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Explanation:

Jet streams which is the ability of the object to move at a high speed due to its power is common among some given set of objects. Some are powered by the objects fuel while others are entirely different.

The above given options are actually affected by the jet streams.

5 0
3 years ago
At one instant, the center of mass of a system of two particles is located on the x-axis at 2.0 cm and has a velocity of (5.0 m/
Nata [24]

Answer:

Explanation:

Given that,

At one instant,

Center of mass is at 2m

Xcm = 2m

And velocity =5•i m/s

One of the particle is at the origin

M1=? X1 =0

The other has a mass M2=0.1kg

And it is at rest at position X2= 8m

a. Center of mass is given as

Xcm = (M1•X1 + M2•X2) / (M1+M2)

2 = (M1×0 + 0.1×8) /(M1 + 0.1)

2 = (0+ 0.8) /(M1 + 0.1)

Cross multiply

2(M1+0.1) = 0.8

2M1 + 0.2 =0.8

2M1 = 0.8-0.2

2M1 = 0.6

M1 = 0.6/2

M1 = 0.3kg

b. Total momentum, this is an inelastic collision and it momentum after collision is given as

P= (M1+M2)V

P = (0.3+0.1)×5•i

P = 0.4 × 5•i

P = 2 •i kgm/s

c. Velocity of particle at origin

Using conversation of momentum

Momentum before collision is equal to momentum after collision

P(before) = M1 • V1 + M2 • V2

We are told that M2 is initially at rest, then, V2=0

So, P(before) = 0.3V1

We already got P(after) = 2 •i kgm/s in part b of the question

Then,

P(before) = P(after)

0.3V1 = 2 •i

V1 = 2/0.3 •i

V1 = 6 ⅔ •i m/s

V1 = 6.667 •i m/s

4 0
3 years ago
Raw sewage is raised vertically by 5.49m in the amountof
uranmaximum [27]

Answer:

          P = 1235.7646 W

Explanation:

Given data:

height of raised sewage = 5.49 m

rate of sewage =1.89*10^6 lt/day

density of sewage = 1.050 kg/m^3

power is written as

P = \frac{work}{time}

work  = m g h

m - mass = ( \rho V)

  h -height

mass lifted per day = ( 1.89*10^6)(1.050)

                              = 1984500 kg

time = 24 hours* 3600 seconds per hour

powerP = \frac{( 1984500)(9.8)( 5.49)}{(24)(3600)}

          P = 1235.7646 W

5 0
3 years ago
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