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dexar [7]
3 years ago
14

An astronaut on the moon throws a baseball upward. the astronaut is 6ft, 6 in. tall and the initial velocity of the ball is 30 f

t per second. the height s of the ball in feet is given by the equation 2.7 30 6.5, 2 s ï½ ï­ t ï« t ï« where t is the number of seconds after the ball is thrown. (note: see where the initial height and initial velocity values play a role in the equation).

Physics
2 answers:
Ainat [17]3 years ago
5 0
The equation is garbled and the question is missing.

I found this equation for the same statement:

S = - 2.7t ^2 + 30t + 6.5

And one question is: after how many seconds is the ball 12 feet above the moon's surface?

Given that S is the height of the ball, you just have to replace S with 12 and solve for t.

=> 12 = - 2.7 t^2 + 30t + 6.5

=> 2.7t^2 - 30t - 6.5 + 12 = 0

=> 2.7t^2 - 30t + 5.5 = 0

Now you can use the quadratic equation fo find t:

t = { 30 +/- √ [30^2) - 4(2.7)(5.5)] } / (2*2.7)

=> t = 0.186s and t = 10.925 s

Answer: after 0.186 s the ball is at 12 feet over the surface, and again 10.925 s

katovenus [111]3 years ago
3 0

The maximum height of the baseball is about 90 feet

<h3>Further explanation</h3>

Acceleration is rate of change of velocity.

\large {\boxed {a = \frac{v - u}{t} } }

\large {\boxed {d = \frac{v + u}{2}~t } }

<em>a = acceleration ( m/s² )</em>

<em>v = final velocity ( m/s )</em>

<em>u = initial velocity ( m/s )</em>

<em>t = time taken ( s )</em>

<em>d = distance ( m )</em>

Let us now tackle the problem!

<u>Given:</u>

The height s of the ball in feet is given by the equation:

s = -2.7t^2 + 30t + 6.5

To find the velocity function, the above equation will be derived as follows:

v = \frac{ds}{dt}

v = -2(2.7)t^{2-1} + 30

\boxed {v = -5.4t + 30}

At the maximum height, the speed is 0 m/s , then:

v = -5.4t + 30

0 = -5.4t + 30

5.4t = 30

t = 30 \div 5.4

\boxed {t = \frac{50}{9} ~ s}

s = -2.7t^2 + 30t + 6.5

s_{max} = -2.7(\frac{50}{9})^2 + 30(\frac{50}{9}) + 6.5

s_{max} = \frac{539}{6}

\large {\boxed {s_{max} \approx 90 ~ feet} }

<h3>Learn more</h3>
  • Velocity of Runner : brainly.com/question/3813437
  • Kinetic Energy : brainly.com/question/692781
  • Acceleration : brainly.com/question/2283922
  • The Speed of Car : brainly.com/question/568302

<h3>Answer details</h3>

Grade: High School

Subject: Physics

Chapter: Kinematics

Keywords: Velocity , Driver , Car , Deceleration , Acceleration , Obstacle

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3 years ago
A closed container initially holds 50 monatomic Aparticles that have a combined energy of 480 units. After 100 monatomic B parti
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"8 units" is the appropriate answer.

Explanation:

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Now,

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= 480+720

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A car is traveling up a hill that is inclined at an angle θ above the horizontal. Determine the ratio of the magnitude of the no
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Explanation:

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The normal or vertical component of the force is, F_N=mg\ cos\theta

or

F_N=mg\ cos(13).............(2)

The horizontal component of the force is, F_H=mg\ sin\theta

Taking ratio of equation (1) and (2) as :

\dfrac{F_N}{W_c}=\dfrac{mg\ cos\theta}{mg}

\dfrac{F_N}{W_c}=cos(13)

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two forces 3N and 4N act on a body in a direction due north and due East respectively calculate their equivalent​
Lostsunrise [7]

Two forces 3N and 4N act on a body in a direction due north From East, the equilibrant's angle is given by \theta=\tan ^{-1} \frac{3}{4}=36.8^{\circ}.

<h3>What are equilibrium and resultant force?</h3>

The equilibrium force is the balanced force when the net force acting is zero and is the exact opposite of the consequent force. The resultant force is one single force replaced by numerous forces.

<h3>Briefing:</h3>

3N and 4N are the two forces pulling on a body.

The forces work along the North and the East, which are perpendicular to one another.

The resultant of the forces, which is provided by the equilibrant force,

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To know more about equilibrium force visit:

brainly.com/question/12582625

#SPJ9

6 0
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