Missing question: "What is the spring's constant?"
Solution:
The object of mass m=6.89 kg exerts a force on the spring equal to its weight:
When the object is attached to the spring, the displacement of the spring with respect to its equilibrium position is
And by using Hook's law, we can find the constant of the spring:
Answer:
True
Explanation:
Matter can be in the form of a particle or a wave. This is known as the dual nature of matter. This concept was proposed by Louis de Broglie and was named after him. This phenomenon has been observed for all the elementary particles.
The de Broglie wavelength is given by
Where
h = Planck's constant
p = Particles momentum
m = Mass of particle
v = Velocity of particle
600/3 = 200
the slope is 200m/min
OR
600/ (3/60) =
600 x 60/3 =
600 x 20 = 12,000 meters per hour
Answer:
Explanation:
According to heisenberg uncertainty Principle
Δx Δp ≥ h / 4π , where Δx is uncertainty in position , Δp is uncertainty in momentum .
Given
Δx = 1 nm
Δp ≥ h /1nm x 4π
≥ 6.6 x 10⁻³⁴ / 10⁻⁹ x 4 π
≥ . 5254 x ⁻²⁵
h / λ ≥ . 5254 x ⁻²⁵
6.6 x 10⁻³⁴ /. 5254 x ⁻²⁵ ≥ λ
12.56 x 10⁻⁹ ≥ λ
longest wave length = 12.56 n m
Answer:
Explanation:
The change in kinetic energy will be simply the difference between the final and initial kinetic energies: 
We know that the formula for the kinetic energy for an object is:
where <em>m </em>is the mass of the object and <em>v</em> its velocity.
For our case then we have:
Which for our values is:
