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Elis [28]
3 years ago
8

An electric motor consumes 10.8 kJ of electrical energy in 1.00 min . Part A If one-third of this energy goes into heat and othe

r forms of internal energy of the motor, with the rest going to the motor output, how much torque will this engine develop if you run it at 2500 rpm
Physics
1 answer:
lina2011 [118]3 years ago
8 0

Answer:

0.458 N/m

Explanation:

Power = Energy/time

From the question,

Note: two-third of the energy into the motor,

Therefore,

P = 2/3(E)/t................. Equation 1

Where P = power of the motor, E = Electrical Energy, t = time

Given: E = 10.8 kJ = 10800 J, t = 1.00 min = 1/60 s

Substitute into equation 1

P = 10800(1/60)(2/3)

P = 120 W.

But,

The power of a rotating motor is given as,

P = Tω................ Equation 2

Where T = Torque of the engine, ω = angular velocity of the engine

Make T the subject of the equation

T = P/ω............... Equation 3

Given: P = 120 W, ω = 2500 rpm = (2500×0.1047) rad/s = 261.75 rad/s

Substitute into equation  3

T = 120/261.75

T = 0.458 N/m

Then the torque develop in the engine = 0.458 N/m

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Answer:

8.16Kg

Explanation:

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102=1/2 m 5²

m=8.16 Kg

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Explanation:

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The number of neutrons is equal to the atomic number<br> O A True<br> B. False
jonny [76]

The number of electrons in a neutral atom is equal to the number of protons. The mass number of the atom (M) is equal to the sum of the number of protons and neutrons in the nucleus. The number of neutrons is equal to the difference between the mass number of the atom (M) and the atomic number. Therefore, it is true!

6 0
3 years ago
Read 2 more answers
A block of mass 4 kilograms is initially moving at 5m/s on a horizontal surface. There is friction between the block and the sur
emmasim [6.3K]

• Net vertical force on the block:

∑ <em>F</em> = <em>n</em> - <em>w</em> = 0

(<em>n</em> = magnitude of normal force, <em>w</em> = weight)

<em>n</em> = <em>w</em> = <em>m g</em>

(<em>m</em> = mass, <em>g</em> = 9.8 m/s²)

<em>n</em> = (4 kg) (9.8 m/s²) = 39.2 N

• Net horizontal force:

∑ <em>F</em> = -<em>f</em> = <em>m a</em>

(<em>f</em> = mag. of friction, <em>a</em> = acceleration)

We have <em>f</em> = <em>µ</em> <em>n</em> = 0.5 (39.2 N) = 19.6 N, so

-19.6 N = (4 kg) <em>a</em>

<em>a</em> = -4.9 m/s²

With this acceleration, the block comes to a rest from an initial speed of 5 m/s, so that it travels a distance ∆<em>x</em> in this time such that

0² - (5 m/s)² = 2 (-4.9 m/s²) ∆<em>x</em>

∆<em>x</em> = (25 m²/s²) / (9.8 m/s²) ≈ 2.55 m ≈ 2.6 m

8 0
2 years ago
A 120 V potential difference is applied to a space heater that dissipates 674 W during operation. (a) What is its resistance dur
Annette [7]

Answer:

(a) 21.36 ohms

(b) 5.62 A

Explanation:

Parameters given:

Potential difference, V = 120 V

Power, P = 674 W

(a) Power is given as:

P = V²/R

Where R is resistance

=> R = V²/P

R = 120²/674

R = 14400/674

R = 21.36 ohms

(b) Power is also given as:

P = I*V

Where I = Current (time rate of flow of Electric charge)

=> I = P/V

I = 674/120

I = 5.62 A

6 0
2 years ago
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