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lora16 [44]
3 years ago
13

While racing on a flat track a car rounds a curve of 56m radius and instantaneously experiences a centripetal acceleration of 36

m/s how fast was the car going.
25m/s
45m/s
35m/s
2.0 x 10^3 m/s
Physics
1 answer:
Damm [24]3 years ago
7 0

45m/s should be the answer because the acceleration changes into's velocity and goes towards the centre in which  is 56/ms that equals v^2/R  the speed at the instant.


Hope this helped


Regards, ShaggySnaps

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<h3>What is the USB?</h3>

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A USB 2.0 requires 480 Mbps for data transfer speed while USB 3.0 requires 4800 Mbps.

A USB 2.0 has the ability to use a maximum power of 500 mA, while USB 3.0 can make use of up to 900 mA.

From the given information, It is stated that the drive requires a minimum of 400 Mbps and at least 900 mA;

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50.0 meters away from a building. Tip of the building makes an angle of 63.0° with the horizontal. What is the height of the bui
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Answer:

98.13m

Explanation:

Complete question

Daniel is 50.0 meters away from a building. Tip of the building makes an angle of 63.0° with the horizontal. What is the height of the building

CHECK THE ATTACHMENT

From the figure, using trigonometry

Tan(θ ) = opposite/adjacent

Where Angle (θ )= 63°

Opposite= X = height of the building

Adjacent= 50 m

Then substitute the values we have

Tan(63)= X/50

1.9626= X/50

X= 1.9626 × 50

X= 98.13m

Hence, the height of the building is 98.13m

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2 years ago
An electron moving in a direction perpendicular to a uniform magnetic field at a speed of 1.6 107 m/s undergoes an acceleration
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Answer:

B = 0.024T positive z-direction

Explanation:

In this case you consider that the direction of the motion of the electron, and the direction of the magnetic field are perpendicular.

The magnitude of the magnetic force exerted on the electron is given by the following formula:

F=qvB     (1)

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Then, the magnitude of the magnetic field is 0.024T and its direction is in the positive z-direction

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