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3 years ago

13

While racing on a flat track a car rounds a curve of 56m radius and instantaneously experiences a centripetal acceleration of 36

m/s how fast was the car going.
25m/s
45m/s
35m/s
2.0 x 10^3 m/s

1 answer:

Damm [24]3 years ago

7 0

45m/s should be the answer because the acceleration changes into's velocity and goes towards the centre in which is 56/ms that equals v^2/R the speed at the instant.

Hope this helped

Regards, ShaggySnaps

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lys-0071 [83]

Answer:

The object will have an upward acceleration

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- The force of gravity, $W$ , (also known as weight of the object), downward

Therefore, the net force on the box is:

$F_{net}=F_p -W$

Here, we know that force applied is equal or greater than the weight, so

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And therefore the net force is greater than zero:

$F_{net}\geq 0$ (1)

According to Newton's second law of motion, the net force on the box is equal to the product between its mass and its acceleration:

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Therefore, the box will have an upward acceleration.

In this case force example we have:

$F_p = 100 N\\W = 40 N$

So the mass of the box is

$m=\frac{W}{g}=\frac{40}{10}=4 kg$

So the net force is

$F_{net}=F_p-W=100-40=60 N$

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Answer:

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Given:

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As we have charge on one electron $1.602\times 10^{-19}\ C$

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