A(n)=ar^(n-1) and we can find the rate upon using the ratio of two points...
50/1250=1250r^2/1250r^0
1/25=r^2
r=1/5 so
a(n)=1250(1/5)^1=250
...
You could have also found the geometric mean which is actually quite efficient too...
The geometric mean is equal to the product of a set of elements raised to the 1/n the power where n is the number of multiplicands...in this case:
gm=(1250*50)^(1/2)=250
Answer:
[22.57 ± 2.776]
Step-by-step explanation:
Hello!
You have the 95% Confidence Z-interval (21.182;23.958), the mean X[bar]= 22.57 and the sample size n=25.
The formula for the Z interval is
[X[bar] ± 
]
The value of Z comes from tha standard normal table:
The semiamplitude (d) or margin of error (E) of the interval is:
E or d= (Upperbond- Lowerbond)/2 = (23.958-21.182)/2 = 2.776
[X[bar] ± E]
[22.57 ± 2.776]
I hope it helps!
Answer:
x = 8√3
Step-by-step explanation:
Using the Pythagorean Theorem:
a² + b² = c²
x² + 8² = 16²
x² + 64 = 256
x² = 192
√x² = √192
x = √64 √3
x = 8√3
There is a percent formula that can solve all of these...
is / of = % / 100
what percent is 32 out of 80...
% = x...because this is what we r looking for
is = 32
of = 80
now sub into the formula
32/80 = x/100
cross multiply because this is a proportion
(80)(x) = (32)(100)
80x = 3200
x = 3200/80
x = 40......so 32 is 40% of 80
12 is 60% of what number...
is = 12
% = 60
of = x
sub
12/x = 60/100
cross multiply
(60)(x) = (12)(100)
60x = 1200
x = 1200/60
x = 20.....so 12 is 60% of 20
what is 30% of 70
is = x
% = 30
of = 70
x / 70 = 30/100
(100)(x) = (30)(70)
100x = 2100
x = 2100/100
x = 21.....so 21 is 30% of 70
what is 40% of 75
is = x
% = 40
of = 75
x / 75 = 40/100
(100)(x) = (75)(40)
100x = 3000
x = 3000/100
x = 30....so 30 is 40% of 75
the pic
what is 40% of 35
is = x
% = 40
of = 35
x/35 = 40/100
(100)(x) = (35)(40)
100x = 1400
x = 1400/100
x = 14.....so 14 is 40% of 35....14 goes in the box
Any integer's sum and the reverse is equal to zero. You can add two positive integers the result will always be a positive sum, including two negative whole numbers dependable yields a negative aggregate. To discover the whole of a positive and a negative number, take the outright estimation of every number and after that subtract these qualities.
