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3 years ago

4(x-11)^2=25

1 answer:

8 0

Expand the square: 4(x-11)^ =25
4(x-11)(x-11)=25

Distribute : 4(x-11)(x-11)=25
4(x(x-11)-11(x-11))=25

Distribute: 4(x(x-11)-11(x-11))=25
4(x^-11x-11(x-11))=25

Solution: x=17/2
x=27/2

hope that helps

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3 years ago

The dimensions of a rectangle are such that its length is 3 in. more than its width. If the length were doubled and if the width

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The length of the rectangle is 11 inch and its width is 8 inch.

Step-by-step explanation:

Given:

Rectangle $(R_1)$ and rectangle $(R_2)$ .

Let the width of the rectangle be 'x' inch.

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Now for rectangle $(R_2)$ its width is decreased by 1 inch and length is doubled,the area $(A_2)$ will increased by 66 sq-inch.

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Plugging the values of $A_2$ in terms of $A_1$ .

⇒ $A_1+66= (x-1)(2x+6)$

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3 years ago

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<em>Also I was plotting the graph so It might take too long. </em>

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