Question

The area of a rectangular is (x^3-5x^2+3x-15), and the width of the rectangular is (x^2+3). If area = length x width, what is the length of the rectangle?

Answer 1

Hope this answer is helpful. It is not x+5. It is x-5.

Answer 2

Answer:

Option D. (x -5)

Step-by-step explanation:

Area of the rectangle is given as A = (x³ - 5x² + 3x - 15)

The width of the rectangle is W = (x² + 3)

Then we have to find the length (L) of the rectangle.

We know that area A = L× W

By putting the values of L and A

(x³- 5x² + 3x -15) = L× (x² + 3)

$L=\frac{x^{3}-5x^{2}+3x-15}{x^{2}+3}$

Now we factorize the numerator first

(x³-5x²+3x-15) = x²(x - 5) + 3(x - 5) = (x² + 3)(x - 5)

Now $L=\frac{(x^{2}+3)(x-5)}{x^{2}+3}=(x-5)$

Therefore Option D (x - 5) is the answer.