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3 years ago

The matrix equation below represents a two variable linear system. Are there solutions? Explain.

Mathematics

2 answers:

almond37 [142]3 years ago

9 0

Answer:

The coefficient matrix is singular, so there are no solutions or infinite solutions.

The two equations in the linear system are the same, so there are infinite solutions.

Yes, there are solutions

Step-by-step explanation:

Marrrta [24]3 years ago

3 0

Answer:

The coefficient matrix is singular, so there are no solutions or infinite solutions.

The two equations in the linear system are the same, so there are infinite solutions.

Yes, there are solutions

Step-by-step explanation:

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Could someone please help me:) I am stick and I am not sure what to do

Delicious77 [7]

Answer:

Part 5.1.1:

$\displaystyle \cos 2A = \frac{7}{8}$

Part 5.1.2:

$\displaystyle \cos A = \frac{\sqrt{15}}{4}$

Step-by-step explanation:

We are given that:

$\displaystyle \sin 2A = \frac{\sqrt{15}}{8}$

Part 5.1.1

Recall that:

$\displaystyle \sin^2 \theta + \cos^2 \theta = 1$

Let θ = 2A. Hence:

$\displaystyle \sin ^2 2A + \cos ^2 2A = 1$

Square the original equation:

$\displaystyle \sin^2 2A = \frac{15}{64}$

Hence:

$\displaystyle \left(\frac{15}{64}\right) + \cos ^2 2A = 1$

Subtract:

$\displaystyle \cos ^2 2A = \frac{49}{64}$

Take the square root of both sides:

$\displaystyle \cos 2A = \pm\sqrt{\frac{49}{64}}$

Since 0° ≤ 2A ≤ 90°, cos(2A) must be positive. Hence:

$\displaystyle \cos 2A = \frac{7}{8}$

Part 5.1.2

Recall that:

$\displaystyle \begin{aligned} \cos 2\theta &= \cos^2 \theta - \sin^2 \theta \\ &= 1- 2\sin^2\theta \\ &= 2\cos^2\theta - 1\end{aligned}$

We can use the third form. Substitute:

$\displaystyle \left(\frac{7}{8}\right) = 2\cos^2 A - 1$

Solve for cosine:

$\displaystyle \begin{aligned} \frac{15}{8} &= 2\cos^2 A\\ \\ \cos^2 A &= \frac{15}{16} \\ \\ \cos A& = \pm\sqrt{\frac{15}{16}} \\ \\ \Rightarrow \cos A &= \frac{\sqrt{15}}{4}\end{aligned}$

In conclusion:

$\displaystyle \cos A = \frac{\sqrt{15}}{4}$

(Note that since 0° ≤ 2A ≤ 90°, 0° ≤ A ≤ 45°. Hence, cos(A) must be positive.)

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3 years ago

Can someone help me with this question please

erastovalidia [21]

for 1st

use the formula of inlargement

A(x,y)when enlarging by scale factor k gives A'(kx,ky)

for 2nd

(2a+3)-(a-5)(2a+2)+a^2

3y(7y-8)

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4 years ago

bella needs identical strips of ribbon measuring 3.5 feet she has 85 feet in ribbon in total how many pieces of ribbon can she c

miss Akunina [59]

Bella can cut about 24 pieces because you have to divide 85 feet by 3.5 feet to find out how many pieces which is 24.285 and so on but you just round to 24.

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4 years ago

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Mr. Gephart is traveling from his house to the history museum. How many meters will he travel to the museum? The distance from h

katovenus [111]

By using relation between metre and kilometre we got that if The distance from home to the history museum is six and seven-tenths kilometres then he travel 67000 m

What is relation between metre and kilometre?

Relation between metre and kilometre is that 1 kilometre =1000 metre

we know that kilometre and metre are two units of distance and we can convert data from one to another using their relation

Now here given distance is in kilometre

and distance is67 kilometre

We can convert 67 kilometre in metre as

67 kilometre = 67 $\times$ 1000metre

67 kilometre = 67000 metre =67000 m

By using relation between metre and kilometre we got that if The distance from home to the history museum is six and seven-tenths kilometres then he travel 67000 m

To know more about distance visit : brainly.com/question/17273444

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3 years ago

Suppose the radius of a circle is 2. What is its area?

Mila [183]

The area would be 12.57
Hope that helps you! :)

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