I'd use synthetic div. here, with 2 as my divisor:
________________
2 / 1 -11 18
2 -18
----------------------------
1 -9 0
Note that the coefficients of the missing factor are given here and are 1 and -9. Thus, (x-9) is the missing factor.
Answer:
800 bacteria
Step-by-step explanation:
Answer of this question depend upon number of hours at the end of day
Let Take Full Day of 24 hrs
Colby bacteria will doubled 12 times ( doubled once in 2hrs => 24/2 = 12)
Colby bacteria at end of day = 50 * 2¹²
Jaquan bacteria will doubled 8 times ( doubled once in 3hrs => 24/3 = 8)
Let say Jaquan bacteria at start of Day = J
Jaquan bacteria at end of day = J * 2⁸
Equating Both
J * 2⁸ = 50 * 2¹²
=> J = 50 * 2⁴
=> J = 50 * 16
=> J = 800
Jaquan will start with 800 Bacteria
2((x+2)(x+2)}-4=28
2{x^2 + 4x + 4}-4=28
2x^2 +4x=28
2(x^2+2x)=28
x^2+2x=28/2
x^2+2x=14
No, line graphs are used only to show change over time
Answer:
3 (5x+2y = 0)
2 (2x – 3y = -19)
Step-by-step explanation:
5x+2y=0 (1)
2x-3y=-19 (2)
To eliminate y from the first two equation when applying the linear combination method
We will multiply y Equation (1) and (2) with 3 and 2 respectively so that the coefficients of y in the two equations +6 and -6 respectively
3(5x+2y=0)
2(2x-3y=-19)
We have,
15x+6y=0 (3)
4x-6y= -38 (4)
Add Equation (3) and (4)
19x=-38
x= -2
Substitute x= -2 into (1)
5x+2y=0
5(-2)+2y=0
-10+2y=0
-10= -2y
y=-10/-2
=5
y=5, x=-2
