Check the picture below.
so the lunchbox is really a semi-circle with a radius of 3, sitting on top of a square of 6x6, with a lenght of 10.
the volume of the lunchbox then will be the area of the semi-circle and square times the length.
Answer:
2/3
Step-by-step explanation:
Answer:
A. ΔDGH ≅ ΔFEH
Step-by-step explanation:
We are given the proof of GH ≅ EH and DH ≅ FH.
Now, previous to step 7, we have obtained,
Step 5: ∠HGD ≅ ∠HEF and ∠HDG ≅ ∠HFE
Step 6: DG ≅ EF as opposite sides of a parallelogram are congruent.
Since, we have that two angles of the triangles are congruent and their including sides are also congruent.
Thus, by Step 7 i.e. ASA criterion for congruence, we get that the corresponding triangles are also congruent.
Hence, we get, ΔDGH ≅ ΔFEH.
Step-by-step explanation:
Answer: 90
cuz if you use the ruler thing it gives you 90 trust me
The answer is when you divide -5 1/3 and 2 3/4 is -1 31/33