is the polynomial of one variable with second-order and
is the polynomial of two variables with third-order
<h3>What is polynomial?</h3>
Polynomial is the combination of variables and constants in a systematic manner with "n" number of power in ascending or descending order.
We have polynomials:
and

For 
In this polynomial, the number of variables is one and the maximum power of x is 2, therefore:
This is the polynomial of one variable with second order.
In polynomial,
there are two variables x and y.
The maximum power of x is 3( x has a power of 2 and y has a power of 1)
This is the polynomial of two variables with third order.
Thus,
is the polynomial of one variable with second-order and
is the polynomial of two variables with third-order.
Learn more about Polynomial here:
brainly.com/question/17822016
Assuming the first 5 terms are:
n = 0
n = 1
n = 2
n = 3
n = 4
a) 4n + 4
4(0) + 4 = 4
4(1) + 4 = 8
4(2) + 4 = 12
4(3) + 4 = 16
4(4) + 4 = 20
b) 8n + 3
8(0) + 3 = 3
8(1) + 3 = 11
8(2) + 3 = 19
8(3) + 3 = 27
8(4) + 3 = 35
c) 18 - 3n
18 - 3(0) = 18
18 - 3(1) = 15
18 - 3(2) = 12
18 - 3(3) = 9
18 - 3(4) = 6
Answer: isn't it 21 then?
Step-by-step explanation:
kinda bad at math haha
Answer:
<u>B. 2</u>
To find MAD, find the mean of the set, then find how far each number is from the mean. Next, find the mean of THAT set of numbers. Yea, I know it's a bit confusing... don't worry!
Find the mean of the set:
12 + 10 + 10 + 8 + 6 + 7 + 7 + 12
72
72 / 8
<u>9</u>
Find how far each number is from 9:
12 - 9 = <u>3</u>
10 - 9 = <u>1</u>
10 - 9 = <u>1</u>
9 - 8 = <u>1</u>
9 - 6 = <u>3</u>
9 - 7 = <u>2</u>
9 - 7 = <u>2</u>
12 - 9 = <u>3</u>
Find the mean of that number set:
{3, 1, 1, 1, 3, 2, 2, 3}
3 + 1 + 1 + 1 + 3 + 2 + 2 + 3
16
16 / 8
<u>2</u>
<u>So the answer is 2!</u>
Not so hard after all :D
Represent the length and width by L and W. Then L = W + 4.
Using the perimeter formula: P = 2L + 2W = 68 ft = 2W) + 2(W+4).
Solve for W: 68 = 2W + 2W + 8, or 4W = 60. Thus, W = 15 and L = 19.
The dimensions of the rectangle are 15 by 19 feet.