Under what condition will a glass lens placed in a transparent medium becomes invisible??
1 answer:
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Given:
F = ax
where
x = distance by which the rubber band is stretched
a = constant
The work done in stretching the rubber band from x = 0 to x = L is
![W=\int_{0}^{L} Fdx = \int_{0}^{L}ax \, dx = \frac{a}{2} [x^{2} ]_{0}^{L} = \frac{aL^{2}}{2}](https://tex.z-dn.net/?f=W%3D%5Cint_%7B0%7D%5E%7BL%7D%20Fdx%20%3D%20%5Cint_%7B0%7D%5E%7BL%7Dax%20%5C%2C%20dx%20%3D%20%5Cfrac%7Ba%7D%7B2%7D%20%20%5Bx%5E%7B2%7D%20%5D_%7B0%7D%5E%7BL%7D%20%3D%20%20%5Cfrac%7BaL%5E%7B2%7D%7D%7B2%7D%20)
Answer:
F = ax
where
x = distance by which the rubber band is stretched
a = constant
The work done in stretching the rubber band from x = 0 to x = L is
Answer:
Answer:
Impulse = 10.36 kg m/s
average force = 172.667 N
Explanation:
given data
mass = 0.280 kg
speed = 15.0 m/s
speed = 22.0 m/s
to find out
impulse and magnitude of the average force
solution
we know that Impulse is change in momentum that is
initial momentum = mass × speed ..........1
initial momentum = 0.28 × (15)
initial momentum = 4.2 kg m/s
Final momentum = mass × speed ..........2
Final momentum = 0.28 × (-22)
Final momentum = -6.16 kg m/s
so now we get Impulse that is
Impulse = 4.2 - (-6.16)
Impulse = 10.36 kg m/s
and
average force will be
average force = impulse ÷ time
average force =
average force = 172.667 N